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Ivenika [448]
3 years ago
8

Christopher bought a new watch at the store when they were having a 20% percent off sale. If the regular price of the watch was

$48 how much did Christopher pay with the discount?
Mathematics
1 answer:
MrMuchimi3 years ago
6 0
$38.40
48 x .2 = 9.6
48 - 9.6 = 38.4 
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A company pays its employees a fixed base salary and a commission based on sales. The scatter plot below shows the total earning
Monica [59]

I'm assuming the question is

A company pays its employees a fixed base salary and a commission based on sales. The scatter plot shows the total earning of an employee of the company (y) based on sales (x):

Plot the ordered pairs 0, 10 and 100, 20 and 200, 30 and 300, 40 and 400, 50 and 500, 60

Which function best represents the data in the scatter plot? (1 point)

y = 0.1x + 10

y = 0.1x − 10

y = 0.1x + 1

y = 0.2x − 1

So thus your answer would be y = 0.1x + 10

5 0
3 years ago
The following angles are supplementary find the missing angle measure
nekit [7.7K]

Answer:

<em>x = 62°, y = 103°</em>

Step-by-step explanation:

<u>Supplementary Angles</u>

Two angles are called <em>supplementary</em> when their measures add up to 180 degrees.

The image shows two pairs of supplementary angles. We have to find the value of the unknown variable.

The first drawing shows supplementary angles x and 118°. They must satisfy the equation:

x + 118° = 180°

Subtracting 118°:

x = 180° - 118°

x = 62°

From the second drawing, we set up the equation:

y + 77° = 180°

Subtracting 77°:

y = 180° - 77°

y = 103°

6 0
2 years ago
PLEASE ANSWER ASAP!! for what value of y must LMNP be a parallelogram?
barxatty [35]
There all 67 degrees
6 0
3 years ago
In solving for systems of equations, by graphing, im sorry but I really need help, with one question, y= 2x + 3
OLga [1]
2x=3-y so collect the likes term which is xy= 3\2
6 0
3 years ago
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Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$
Blizzard [7]
\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}

a^{81}\equiv1^{81}\equiv1\pmod7

b^{91}\equiv2^{91}\pmod7

2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7
8\equiv1\pmod7
2\equiv2\pmod7
\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7

c^{27}\equiv6^{27}\pmod7

6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7

\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7
6 0
3 years ago
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