"find expressions for the mean and standard deviation of y if this variable is determined by the expression y

1 answer:

3 0

expressions for the mean and standard deviation of y if this variable is determined by the expression y $\lim_{n \to \infty} a_n$ $\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]$

You might be interested in

If 0.142857142857......is expressed in the form m/n, then what is the value of (2m + n)?

frosja888 [35]

Answer:

The value will be: 1,285,713

Step-by-step explanation:

We have the number:

N = 0.142857...

Such that we have 6 decimals after the decimal point that repeat infinitely.

Then let's start by multiplying our number by 1,000,000 (same number of zeros as decimals after the decimal point)

Then we get:

1,000,000*N = 142,857.142857...

Now let's subtract N from both sides:

1,000,000*N - N = 142,857.142857... - 0.142857...

999,999*N = 142,857

Now let's isolate N

N = 142,857/999,999

Here is our number expressed in the form m/n, where:

m = 142,857

n = 999,999

Then the value of (2*m + n) is:

(2*142,857 + 999,999) = 1,285,713

5 0

3 years ago

Why is 3 to the power 0 = 1

Nostrana [21]

When we raise something to a power, it really justs means we are multiplying it by itself. 3^2 (3 to the power of 2) means that we are mutliplying 3 by itself: 3•3 = 9 or 3^2 = 9 (there are two 3's)

However, when we rasie something to the 0 power, it equals 1. That is because we are multiplying it by itself 0 times. We are not multiplying it by zero, we are effectively doing nothing at all. 3^0 = 1

4 0

3 years ago

15 points. Please answer as soon as possible.

abruzzese [7]

Answer:

A. $\frac{(a-b)^{2} +b^{2} }{a^{2}}$

Step-by-step explanation:

So to get the area of a square, we need to find the length of one side.

We know the length of the larger square is a, so the area of the larger cube is $a^{2}$

We can find the length of a side of the smaller square by using pythagoreans theorem to find the hypotenuse of the triangle formed in the bottom left corner. The length of one side along the x axis is a - b, and the length of the other side, along the y-axis, is b.

We can plug it into pythagoreans theorem to get

$(a-b)^{2} +b^{2} = C^{2}$ (C represents the length of one side of the smaller square, and the hypotenuse of the triangle)