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marshall27 [118]
3 years ago
12

Multiply. Express your answer in simplest form.

Mathematics
1 answer:
DENIUS [597]3 years ago
8 0

Answer:

Bet

Step-by-step explanation:

It’s a simple one to write. There are many trios of integers (x,y,z) that satisfy x²+y²=z². These are known as the Pythagorean Triples, like (3,4,5) and (5,12,13). Now, do any trios (x,y,z) satisfy x³+y³=z³? The answer is no, and that’s Fermat’s Last Theorem.

On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?

That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)

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The answer to this question should be H

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3 years ago
In a flock of geese there are 7 female geese for every 4 male geese. There are 21 female geese. What is the total number of gees
weeeeeb [17]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

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❖ 33 geese

7/4 x 21 = 12

21 + 12 = 33

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6 0
3 years ago
1. 9 <br> 2. 6 <br> 3. 3<br> 4. 81<br> Help plz giving out brianlest and god bless you
Karo-lina-s [1.5K]
4) 81 is the correct ans
5 0
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Read 2 more answers
The price of a new cell phone is $199. Eduardo’s cell phone carrier is offering a 15% off coupon, and the store is offering a $5
Blizzard [7]
The answer is $119.15
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Purchasing A regional survey found that 70% of all families who indicated an intention to buy a new car bought a new car within
zheka24 [161]

Answer:

If a family chosen at random bought a car, we need to find the probability that the family had not previously indicated an intention to buy a car = P(I'|B) = 0.3362

Step-by-step explanation:

Let the event that a family that intends to buy a car be I

Let the event that a family does not intend to buy a car be I'

Let the event that a family buys a car in those 3 months be B

Let the event that a family does not buy a car in those 3 months be B'

Given,

P(B|I) = 0.70

P(B|I') = 0.10

P(I) = 0.22

P(I') = 1 - P(I) = 1 - 0.22 = 0.78

If a family chosen at random bought a car, we need to find the probability that the family had not previously indicated an intention to buy a car = P(I'|B)

The conditional probability P(A|B), is given as

P(A|B) = P(A n B) ÷ P(B)

So,

P(B|I) = P(B n I) ÷ P(I)

P(B n I) = P(B|I) × P(I) = 0.70 × 0.22 = 0.154

P(B|I') = P(B n I') ÷ P(I')

P(B n I') = P(B|I') × P(I') = 0.10 × 0.78 = 0.078

P(B) = P(B n I) + P(B n I') = 0.154 + 0.078 = 0.232

P(B') = 1 - 0.232 = 0.768

P(I'|B) = P(B n I') ÷ P(B)

= 0.078 ÷ 0.232 = 0.3362

Hope this Helps!!!

8 0
3 years ago
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