2 years ago

What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?

1 answer:

6 0

f(x) = 112 - kx
f(-3) = 112 - k(-3)
f(-3) = 112 - (-3k)
f(-3) = 112 + 3k
121 = 112 + 3k
- 112 - 112
      9 = 3k
      3    3
      3 = k

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