Express √3 + i in polar form:
|√3 + i| = √((√3)² + 1²) = √4 = 2
arg(√3 + i) = arctan(1/√3) = π/6
Then
√3 + i = 2 (cos(π/6) + i sin(π/6))
By DeMoivre's theorem,
(√3 + i)³ = (2 (cos(π/6) + i sin(π/6)))³
… = 2³ (cos(3 • π/6) + i sin(3 • π/6))
… = 8 (cos(π/2) + i sin(π/2))
… = 8i
V(S)=S^3/6
S=6
V(6)=6^3/6=6^2=36
Answer:
The first term is:
Step-by-step explanation:
The arithmetic sequence is defined by
where
is the first term
is the common difference
as
the 17th term of an arithmetic sequence is 51.
i.e. 
so
∵ 
, , 
∵ 
Therefore, the first term is:
Observe.
6/2(1+2)
6/2(3)
6/6
1
Thus, the answer is: 1
The correct answer would be,
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