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2 years ago

The numbers of pages in the books in a library follow a normal distribution. If the mean num

Mathematics

1 answer:

bogdanovich [222]2 years ago

7 0

Answer:

For the answer to the question above, the numbers of pages in the books in a library follow a normal distribution. If the mean number of pages is 180 and the standard deviation is 30 pages, you can conclude that about 16% of the books have fewer than 150 pages.

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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

I'm supposed to write out an algebraic equation, and then solve the equation. If you can help me, with work shown, you'll get vo

Arada [10]

Answer:

simple just follow me and mark it brainliest

Step-by-step explanation:

LET THE THREE CONSECUTIVE EVEN INTEGERS BE

(x+2) ,(x+4) ,(x+6)

then

according to the question

4(x+2) – (x+6) = 2(x+4) + 6

4x + 8 – x – 6= 2x + 8+6

3x +2 = 2x + 14

3x – 2x= 14 –2

x= 12

the numbers are

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2 years ago

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Solve 5.7y - 3.9y I is not smart lolz

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5.7 of anything minus 3.9 of the same thing leaves 1.8 of them.

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3 years ago

At a hardware store a bag holds up to 1 pound of nails. Each penny nail (x) weighs 0.05 pounds and each wood nail (y) weighs 0.1

posledela

For this answer, you multiply the weight of each penny nail by x and the weight of each wood nail by y. If the bag holds one pound of nails, you would use the inequality ≤.

.05x + 0.1y ≤ 1

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2 years ago

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50 POINTSSSSS! PLEASE HELP! Josefina is inscribing a square in a circle with center c. She first uses a straight edge to draw a

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Use a straight Edge to connect the four points

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2 years ago

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