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Len [333]
3 years ago
12

What is the weight of a bowling ball with a 5 in. radius if we know that one cubic inch weighs 1/100th of a pound?

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
6 0
<h2>Greetings!</h2><h3>To find the total area of the bowling ball, which we presume is spherical, the equation is:</h3>

\frac{4}{3}πr³

<h3>So we know that the radius is 5, so we can substitute that into the equation:</h3>

\frac{4}{3} x π x 5³ = 523.599 or 524 to 1dp.

<h3>Seeing as this is 524 cubic inches, we can convert this into pounds by dividing this by 100, because one cubic inch weights \frac{1}{100} as stated.</h3>

524 ÷ 100 = 5.24lb

<h3>So your answer would be B, 5.24lb.</h3>
<h2>Hope this helps!</h2>

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Answer:

264

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

1. Re-write your equation so that x is on the right and y is on the left:

x = -4y ---> y = (-1/4)x

slope = -1/4. y-intercept = (0,0)

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slope m = (y2 - y1) / (x2 - x1)

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therefore, y - y1 = mx - x1 ---> y - 4 = -2x

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Answer:

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Givens

Work week = 40 hours

Paid 7.50 an hour.

Sells 6300 worth of goods.


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Answer 615 <<<<

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Answer:

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