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3 years ago

Which graph represents the solution for x2 + x - 12 > 0?

Mathematics

2 answers:

igomit [66]3 years ago

6 0

Answer:it’s c on edge, sorry i’m late but for anyone else who needs help it’s c !!

Step-by-step explanation:

lora16 [44]3 years ago

4 0

Answer:

C. on edg2020

Step-by-step explanation:

Hope this helps!!! Have a great day!!! : )

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A grab-bag contains 30 packages worth $.65 each, 10 packages $.60 cents each, and 15 packages worth $.30 each. What is the expec

Dennis_Churaev [7]

The answer would be 0.03.
What I did was 50/15 which would get me 0.0333333333333. But since money can only the cents can only have two numbers. So it would be 0.03 as the answer. So it’s the answer d.

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3 years ago

Solve this riddle: I am an odd number. I an less than 100. The some of my digit is 12. I am a multiple of 15. What number am I?

tiny-mole [99]

The answer to this is 75

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3 years ago

Can someone help me?It's urgent and thank you!

lidiya [134]

Answer:

y = square root x2 - 5

Step-by-step explanation:

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3 years ago

Read 2 more answers

Helpppppppp pleaseeeeee

olga nikolaevna [1]

Answer:

7a + b - 16c

Step-by-step explanation:

So we have

7a-3b+c-8c+4b-9c

When it comes to problem like these, you need to combine like terms.

There's only one 'a' number, so that one remains the same.

Next, we have -3b and 4b. (-3b+4b)= b

Finally, there's (c-8c-9c).

(-8c-9c)= -17c

Take that and add the positive 'c' to it.

(-17c+c)= -16c

Put it all together now to get:

7a + b - 16c

I hope that helped and helped you understand at least a little

6 0

3 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$