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iris [78.8K]
3 years ago
15

Peter walked for 2/5 mile to Fred's house and then 1/2 mile to the park. How can he write 2/5 and 1/2 as pair of fractions with

common denominattor?
Mathematics
2 answers:
andre [41]3 years ago
6 0
4/10 and 5/10 i think unless i totally failed
Volgvan3 years ago
6 0
2/5 and 1/2
If you multyply 5 and 2 you will get 10 which is a common denominator of both numbers (5 and 2)
Remember that if you do something to your denominator you must also do it to your numerators.
So, 5 multiplied by 2 is 10.... Put both denominators as 10
?/10 and ?/10
Now think... What multiplied by 5 gave me 10? The answer is 2. So, you multiply 2 and 2 in order to give you 4.
Now we have:
4/10 and ?/10
Now you think.... What multiplied by 2 gave me 10? The answer is 5. So you do 1 multiplied by 5 which gives you 5.
Now you have:
4/10 and 5/10
Thats the answer!
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What is the vertex of the graph of y = −1(x − 2)2 + 3?<br> (3,-2)<br> (-2,3)<br> (3,2)<br> (2,3)
aleksley [76]
The vertex form is y=a(x-h)²+k
the vertex is (h,k)
so

y=-1(x-2)²+3
compare to
y=a(x-h)²+k
2=h and 3=k
the vertex is  (2,3)
4th option
8 0
3 years ago
Read 2 more answers
Jane drives at a constant rate of 45 miles per hour for 4 hours. How far will she have traveled in that time?
bearhunter [10]
180 miles per hour. 45*4 to get the answer.<span />
6 0
3 years ago
The graphs show the amounts in two different bank accounts over several months.
Neko [114]

Answer:

where are the graphs?

Step-by-step explanation:

3 0
3 years ago
Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:
ryzh [129]

First find the critical points of <em>f</em> :

f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7

\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1

\dfrac{\partial f}{\partial y}=6y=0\implies y=0

so the point (1, 0) is the only critical point, at which we have

f(1,0)=-7

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t

Find the critical points of <em>g</em> :

\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0

\implies\sin t=0\text{ OR }1+5\cos t=0

\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi

where <em>n</em> is any integer. We get 4 critical points in the interval [0, 2π) at

t=0\implies f(10,0)=155

t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299

t=\pi\implies f(-10,0)=235

t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299

So <em>f</em> has a minimum of -7 and a maximum of 299.

4 0
3 years ago
Bob sets the price of the plants according to their height in inches. A plant that is 9.5 inches high costs $2.28 in his store.
wel

Answer: $0.24

Step-by-step explanation:

9.5 inches --> $2.28
1 inch--->X
now cross multiply it and get,

9.5X = 2.28*1
X = 2.28/9.5

so its $0.24 per inch

4 0
2 years ago
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