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Vlada [557]
3 years ago
7

Determine if each statement is always, sometimes, or never true.

Mathematics
2 answers:
Tema [17]3 years ago
7 0

1. Parallel lines are always coplanar.

<em>The right answer is </em><em>always.</em>

This is indicated in Figure 1. You can see that the red line and the blue one lie on the same plane, therefore parallel lines are always co-planar.


2. Perpendicular lines are always coplanar.


<em>The right answer is </em><em>always.</em>


This is illustrated in Figure 2. As you can see, the red and blue lines are perpendicular. Notice that the red line lies on the plane M and also on the plane N, and the blue line only lies on the plane N. Therefore, both lines lie on the plane N. In conclusion, perpendicular lines are always coplanar.


3. Distance around an unmarked circle can never be measured.


<em>The right answer is </em><em>never</em>


We need to have a marked circle to measure the distance. So, the distance from the center of the circle to one point of it is the radius. Moreover, the distance between two points of the circle taking a line passing through the center is the diameter of the circle.

Allushta [10]3 years ago
5 0
1.always
2.always
3.never
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Find the area of each figure. round to the nearest tenth if necessary .
Alex787 [66]

We first would divide the Pentagon into two shapes, one a square and the other a triangle. To find the height of the triangle we must minus the 15cm to the 10cm, which gives us 5cm.

5cm= height of triangle

7cm= base of triangle

Then, apply the area of triangle formula

which is: A=(b×h)÷2

so the area would be 17.5cm squared.

For the square, 10= height and the 7=base

The formula for rectangles is:

A=b×h

so, the area is 70cm squared.

if you want the total area add the two area together, which equals 87.5cm squared.

I hope this helps.

7 0
3 years ago
Last month , Luke and Stefen sold candy to raise money for their debate team . Stefen sold 1/5 as much candy as Luke did . If Lu
Natalija [7]

Answer:

3/20

Step-by-step explanation:

stefan sell 1/5 × 3/4 = 3/20 boxes of candy

5 0
3 years ago
For a particular diamond mine, 81% of the diamonds fail to qualify as "gemstone grade". A random sample of 92 diamonds is analyz
Fed [463]

Answer:

68.79% probability that more than 79% of the sample diamonds fail to qualify as gemstone grade

Step-by-step explanation:

We use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 92, p = 0.81

So

\mu = E(X) = np = 92*0.81 = 74.52

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{92*0.81*0.19} = 3.76

Find the probability that more than 79% of the sample diamonds fail to qualify as gemstone grade.

This is 1 subtracted by the pvalue of Z when X = 0.79*92 = 72.68. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{72.68 - 74.52}{3.76}

Z = -0.49

Z = -0.49 has a pvalue of 0.3121

1 - 0.3121 = 0.6879

68.79% probability that more than 79% of the sample diamonds fail to qualify as gemstone grade

4 0
3 years ago
If △NMO ∼ △XYZ, and the area of △NMO is 147 square feet, find the area of △XYZ
sladkih [1.3K]

The area of △XYZ according to the figure is 363ft²

<h3>Area of triangles</h3>

The formula for calculating the area of a triangle is expressed as:

A = 0.5bh

  • b is the base
  • h is the height

<h3>Calculate area of each triangles</h3>

For the triangle  △NMO

Area of  △NMO = 0.5bh

147 = 0.5b(14/12)

147 = 7b/12

7b = 12 * 147

b = 252

b = 252ft

b = 3024in

Get the base of △XYZ

14/3024 = 22/XZ

XZ = 4,752in

Area of △XYZ = 0.5 (4,752)(22)

Area of △XYZ= 52,272in²

Area of △XYZ = 363ft²

Hence the area of △XYZ is 363ft²

Learn more on area of triangles here: brainly.com/question/17335144

6 0
2 years ago
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
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