I think its 97200 i am sorry if it is wrong
A in the answer for this question
Thank you
Using the information given, it is found that the class width for this frequency distribution table is of 1.
In this problem, these following classes are given:
0 – 1 14
2 – 3 1
4 – 5 8
6 – 7 12
8 – 9 12
The classes not given, which are 1 - 2, 3 - 4 and 5 - 6, have values of 0.
The <u>difference between the bounds of the classes is of 1</u>, thus, the class width is of 1.
A similar problem is given at brainly.com/question/24701109
Answer:

Step-by-step explanation:
Let
x ----> the average depth of the resulting layers of ash and rock
we know that
To find out the average depth, divide the cubic kilometers of molten rock by the area where all the ejected material fell.
so

Convert to meters
Remember that

so

Convert to mixed number

182 Let x = width then y = 6x - 91. P (perimeter) = 2x + 2y = 84 then
2(x) + 2(6x - 91) = 84 | 2x + 12x - 182 =84 | 14x = 84 + 182 | 14x = 266 | x = 19 cm
y = 6x - 91 | y = 6 (19) - 91 | y = 114 - 91 | y = 23 cm
Check: P = 2x + 2y | P = 2(19) + 2(23) | P = 38 + 46 | P = 84 cm (Checked)