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nadezda [96]
3 years ago
8

Solve for x eliminate y

Mathematics
1 answer:
AnnZ [28]3 years ago
6 0

Answer:

x = - 6

Step-by-step explanation:

given the 2 equations

3x + 5y = - 13 → (1)

2x - 3y = - 15 → (2)

To eliminate y from the equations we require their coefficients to be equal so that when we add the equations y is eliminated

multiply equation (1) by 3 and equation (2) by 5

9x + 15y = - 39 → (3)

10x - 15y = - 75 → (4)

add (3) and (4) term by term

(9x + 10x) + (15y - 15y) = (-39 - 75 )

19x = - 114 ( divide both sides by 19 )

x = - 6

To find y substitute x = - 6 into either (1) or (2)



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Find the area of the polygon defined by the coordinates (0,-5),(-5,0),(-15,-20),and(-20,-15)
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Area of the polygon defined by the given points is 62.5 sq units

Step-by-step explanation:

Step 1 :    

Let P be the point (-5,0)  Q = (0,-5), R = (-15,-20) and S = (20,-15)

We have to to find the area of the polygon PQRS

Step 2 :

The area of polygon given the vertices (x(x_{1} ,y_{1} ), (x_{2} ,y_{2})  ... (x_{n} ,y_{n} ) is given by

Area  = mod ( (x_{1} y_{2}  - y_{1}x_{2}) + (x_{2} y_{3}  - y_{2}x_{3}) + ... (x_{n} y_{1}  - y_{n}x_{1}) ) ÷ 2

Where  x_{n} is the vertex n's x coordinate , y_{n} is the vertex n's y coordinate

Substituting the corresponding values ,

Area of PQRS = mod ( (25 - 0)+ (0-75) +(300-300) +( 0-75)  ) ÷ 2

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                       = mod (-125) ÷ 2 = 125 ÷ 2 = 62.5 sq units

Step 3 :    

Answer :

Area of the polygon defined by the given points is 62.5 sq units

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