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pentagon [3]
3 years ago
10

(2x^3+4x^2-3)+(6x^3+4x-4)​

Mathematics
2 answers:
sukhopar [10]3 years ago
8 0

Answer:

8x^3 + 4x^2 + 4x -7

Step-by-step explanation:

Add like terms.

zepelin [54]3 years ago
3 0

Answer: everything is explained in the picture

Step-by-step explanation:

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Angie sells blue and yellow balloons. For every 10 blue balloons that are sold, she sells 7 yellow balloons.
natulia [17]
The answer is 340-2=338; 338-100=
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muminat
Yes, this is all correct!
4 0
3 years ago
Kayla buys two pairs of jeans for j dollars each and one shirt for 15 dollars. she has 60 dollars to spend. The equation 2j+ 15-
weeeeeb [17]

Kayla buys two pairs of jeans for j dollars each and one shirt for 15 dollars. The cost of one pair of jeans is $22.5  (twenty-two dollars and fifty cents)

From the given information

  • Let the cost of two pairs of jeans be 2j
  • The cost of 1 shirt = 15
  • Total amount to spent = $60

∴

The equation is said to be expressed as:

  • 2j + 15 - 60 = 0

Collect like terms

  • 2j = 60 - 15
  • 2j = 45

Divide both sides by 2

  • \mathbf{\dfrac{2j}{2}= \dfrac{45}{2}}
  • j = 22.5

Therefore, we can conclude that the cost of one pair of jeans is  $22.5  (twenty-two dollars and fifty cents).

Learn more about cost here:

brainly.com/question/13910351?referrer=searchResults

5 0
2 years ago
Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
3 years ago
One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.
Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 )  pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both  = $ 39

I.e  2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = \frac{39}{6} = \frac{13}{2}

∴ sw = \frac{13}{2} × \frac{3}{2}

or, sw = \frac{39}{4}

Now, the ratio of the amount for swordfish to the amount of salmon = \frac{\frac{39}{4}}{\frac{13}{2}}

I.e The ratio = \frac{6}{4}

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

3 0
3 years ago
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