Area of the shaded region
square cm
Perimeter of the shaded region
cm
Solution:
Radius of the quarter of circle = 12 cm
Area of the shaded region = Area of quarter of circle – Area of the triangle



square cm.
Area of the shaded region
square cm
Using Pythagoras theorem,



Taking square root on both sides of the equation, we get
cm
Perimeter of the quadrant of a circle = 

cm
Perimeter of the shaded region =
cm
cm
Hence area of the shaded region
square cm
Perimeter of the shaded region
cm
Assuming you mean angle ABC and not 2ABC?
Since ray BD bisects angle ABC we can set the two angle measures given equal to each other.
2x+7=4x-41
Solve for x=24
Plug in the x to find angle ABD 2(24)+7=55
therefore angle ABD is 55 and angle DBC is 55 so angle ABC is 110
Answer:
subtract a constant from both sides
Step-by-step explanation:
The first step in solving an equation like this is to get the coefficients and variables by themselves, and to do that, you must separate the coefficients (numbers being multiplied by a variable) from the constant (numbers not being multiplied by a variable). You do this by subtracting the constant from both sides of the equation to ensure that they are equal (you subtract -10 from both sides here (adding 10 to both sides)).
Answer:
vertex = (0, -4)
equation of the parabola: 
Step-by-step explanation:
Given:
- y-intercept of parabola: -4
- parabola passes through points: (-2, 8) and (1, -1)
Vertex form of a parabola: 
(where (h, k) is the vertex and
is some constant)
Substitute point (0, -4) into the equation:

Substitute point (-2, 8) and
into the equation:

Substitute point (1, -1) and
into the equation:

Equate to find h:

Substitute found value of h into one of the equations to find a:

Substitute found values of h and a to find k:

Therefore, the equation of the parabola in vertex form is:

So the vertex of the parabola is (0, -4)
Answer:
93.5 square units
Step-by-step explanation:
Diameter of the Circle = 12 Units
Therefore:
Radius of the Circle = 12/2 =6 Units
Since the hexagon is regular, it consists of 6 equilateral triangles of side length 6 units.
Area of the Hexagon = 6 X Area of one equilateral triangle
Area of an equilateral triangle of side length s = 
Side Length, s=6 Units

Area of the Hexagon
