A 33 gram sample has k value of .1124
(Actually I think the problem SHOULD be worded: A 33 gram sample has k value of -.1124/days)
See attached graphic:
Half-Life = ln (.5) / k
Half-Life = -.693147 / -.1124/days
Half-Life =
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6.1667882562
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days
Source:
http://www.1728.org/halflif2.htm
Answer:
y = x^2 +6x +8
Step-by-step explanation:
The vertex is located at (-3, -1) and the graph rises 1 unit vertically for 1 unit away from the vertex. This means the scale factor is 1 and the vertex form equation can be written as ...
y = a(x -h)^2 +k . . . . . vertex form with scale factor a, vertex (h, k)
__
y = (x -(-3))^3 +(-1) . . . fill in the values we know
y = (x +3)^2 -1 . . . . . simplify signs
y = x^2 +6x +9 -1 . . . eliminate parentheses
y = x^2 +6x +8 . . . . . your equation in standard form
You have to divide , first you have to turn 28 into a fraction , 28 over one , then you have to flip 3/4 into 4/3 then multiply it
Answer:
The rock splashes down when h(t) = 0. Set h(t) = 0 and solve for t using quadratic formula.
0 = − 4.9t^2 + 178t + 325
t = 38.07, -1.74
(Throw away the negative answer, since time can't be negative.)
t = 38.07 sec
Please Mark Brainliest If This Helped!
Using proportions, it is found that it takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.
10 mini-bears weights to 12.1 grams, hence the weight of a mini-bear is of:
12.1/10 = 1.21 grams.
10 regular bears weights to 23.1 grams, hence the weight of a regular bear is of:
23.1/10 = 2.31 grams.
1 super bear weights to 2250 grams, hence the proportion between the <u>weight of a super bear and the weight of a mini-bear</u> is:
2250/1.21 = 1860.
The proportion between the <u>weight of a super bear and the weight of a regular bear</u> is:
2250/2.31 = 974.
The difference of proportions is given by:
1860 - 974 = 886.
It takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.
More can be learned about proportions at brainly.com/question/24372153
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