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Dmitrij [34]
3 years ago
7

In a study of the relationship between geographical mobility (number of times a person has changed residences) and number of fri

ends, Pearson's r2 is reported as .40. Which of the following would be a correct interpretation? Mobility explains 40% of the variation in number of friends There is a strong positive relationship between number of friends and mobility As mobility increases, number of friends decreases Mobility explains 16% of the variation in number of friends
Mathematics
1 answer:
morpeh [17]3 years ago
8 0

Answer:

Option A

Step-by-step explanation:

Given that in a study of the relationship between geographical mobility (number of times a person has changed residences) and number of friends, Pearson's r^2 is reported as .40.

r square, being the coefficient of determination explains the variablity of one variable due to the variability of the other.  Here Mobility explains 40% variation in the number of friends is right answer.

Option B is wrong because r = ±6324, so cannot say positive or negative.

Similarly option c is wrong because we are unsure whether negative correlation.  Option d is wrong since 16% is not right .

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6. Suppose that a fair coin is tossed 2 times, and the result of each toss (H or T) is recorded.
nekit [7.7K]

Answer:

a) S= {HH, HT, TH, TT}

b) P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25

P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5

P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25

And we have the following table:

X     |     0   |     1   |      2

P(X) |  0.25 |  0.5 |  0.25

Step-by-step explanation:

Let's define first some notation

H= represent a head for the coin tossed

T= represent tails for the coin tossed

We are going to toss a coin 2 times so then the size of the sample size is 2^2 = 4

a. What is the sample space for this chance experiment?

The sampling space on this case is given by:

S= {HH, HT, TH, TT}

b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.

The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:

P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25

P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5

P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25

And we have the following table:

X     |     0   |     1   |      2

P(X) |  0.25 |  0.5 |  0.25

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3 years ago
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MissTica

Answer:

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Alex_Xolod [135]

Answer:

1000

Step-by-step explanation:

3,450/3.45=1000

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