Answer:
57.420
Step-by-step explanation:
The y intercept is always the number on the out side next to the slope which is 2.391
Answer:
a
Step-by-step explanation:
Answer:
The system of linear equations is x + y = 64 and x = y + 14.
Given that,
The total number of students is 64 .
Here we assume the x be the number of students in filmmaking club .
And, y be the number of students in yearbook club.
Based on the above information, the calculation is as follows:
x + y = 64
And,
x = y + 14
Therefore,
We can say that
Number of students in yearbook club = 25
And, the number of students in filmmaking club = 39
Answer:
d=10u
Q(5/3,5/3,-19/3)
Step-by-step explanation:
The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane
, then r will have the next parametric equations:

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

Substitute the value of
in the parametric equations:

Those values are the coordinates of Q
Q(5/3,5/3,-19/3)
The distance from Po to the plane

Distance=speed x time
so it would be 28 x 6=168