I wonder if you mean to write
in place of
...
If you meant what you wrote, then we have


If you meant to write
(the cube root of 256), then we could go on to have
![\sqrt[3]{256}=\sqrt[3]{16^2}=\sqrt[3]{(4^2)^2}=\sqrt[3]{4^4}=\sqrt[3]{4^3\cdot4}=4\sqrt[3]4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B256%7D%3D%5Csqrt%5B3%5D%7B16%5E2%7D%3D%5Csqrt%5B3%5D%7B%284%5E2%29%5E2%7D%3D%5Csqrt%5B3%5D%7B4%5E4%7D%3D%5Csqrt%5B3%5D%7B4%5E3%5Ccdot4%7D%3D4%5Csqrt%5B3%5D4)
Answer: For 10 sessions, the cost of the two plans the same.
Step-by-step explanation:
Let x= Number of sessions.
Given: Christian’s Gym charges a one-time fee of $50 plus $30 per session for a personal trainer.
Total charge for x sessions = 50+30x
Nicole's fitness center charges a yearly fee of $250 plus $10 for each session with a trainer.
Total charge for x sessions = 250+10x
When both plan charges the same, then

i.e. For 10 sessions, the cost of the two plans the same.
We have a fraction of two integers, so 25/9 is rational. A rational number is any fraction of two integers (as long as the denominator is not zero).
Answer:
2
Step-by-step explanation:
(-7)^2 - 4*3 *(-2) = 49 + 24 >0
discriminant is positive so 2 real roots
It would be 10 because 6.4 is greater than 5. Correct me if i’m wrong