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3 years ago

M<KGH=x+161,m<FGK=x+41,and m<FGH=180° Find x

Mathematics

1 answer:

Butoxors [25]3 years ago

4 0

Answer: x = -11 ∠FGK = 30° ∠KGH = 150°

Step-by-step explanation:

∠FGK + ∠KGH = ∠FGH Segment Addition Postulate

x + 41 + x + 161 = 180 Substitution

2x + 202 = 180 Simplify (added like terms)

2x = -22 Subtraction Property of Equality

x = -11 Division Property of Equality

∠FGK = x + 41 = (-11) + 41 = 30

∠KGH = x + 161 = (-11) + 161 = 150

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Answer:

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3 years ago

The legs of a 45 45 90 triangle have a length of 8 units what is the length of the hypotenous

Crank

Answer:

11.31 units

Step-by-step explanation:

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3 years ago

Find the volume of the cylinder in terms of pi h = 6 in. and r = 3 in. A 54π in.3 B108π in.3 C324π in.3 D 27π in.3

Orlov [11]

Answer:

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Step-by-step explanation:

we know that

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where

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h is the height of the cylinder

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3 0

3 years ago

I need to find what A and B are

laiz [17]

Answer:

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Step-by-step explanation:

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3 years ago

Of 560 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compared

frutty [35]

Answer:

a) (0.5256,0.5944)

c) Criticism is invalid

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 560

Proportion of mislabeled = 56%

$\hat{p} = 0.56$

a) 90% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.64$

Putting the values, we get:

$0.56\pm 1.64(\sqrt{\dfrac{0.56(1-0.56)}{560}}) = 0.56\pm 0.0344\\\\=(0.5256,0.5944)$

b) Interpretation of confidence interval:

We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.

c) Validity of criticism

Conditions for validity:

$np > 10\\n(1-p)>10$

Verification:

$560\times 0.56 = 313.6>10\\560(1-0.56) = 246.4>10$

Both the conditions are satisfied. This, the criticism is invalid.

8 0

3 years ago