We'll use standard labeling of right triangle ABC, C=90 degrees, legs a, b, hypotenuse c.
11.
Right triangle, cliff peak A, boat B, angle opposite cliff is B=28.9 deg. adjacent leg a=65.7 m, cliff height is leg b.
tan B = b/a
b = a tan B = 65.7 tan 28.9° = 36.3 m
12.
Similar story, boat at B, opposite b=3.5 m, rope c=12 m
sin B = b/c
B = arcsin b/c = arcsin (3.5/12) = 17.0°
13.
c=124 m, A=58°
sin A = a/c
a = c sin A = 124 sin 58 = 105.2 m
14.
That's a hypotenuse c=4-1.2 = 2.8 m to a height b=1.8m so
cos A = b/c
A = arccos b/c = arccos (1.8/2.8) = 50.0°
15.
Not a right triangle, an isosceles triangle. Half of it is a right triangle with hypotenuse one arm, c=9.8 cm and angle opposite half the base of B=62/2=31°. We're after d=2b:
sin B = b/c
b = c sin B
d = 2b = 2 c sin B = 2(9.8) sin 31 = 10.1 cm
Almost equilateral
To get from 40% to 100%, divide by 2 and multiply by 5.
I.e. 40/2 = 20
20 x 5 = 100%
Do the exact same for 102
102/2 = 51
51 x 5 = 255 students
Answer:
SDSDS
Step-by-step explanation:
ASDSD
Answer:
- <u><em>Option B. There will be close to 40 TVs but probably not exactly 40 TVs not showing a sports channel.</em></u>
Explanation:
There are a total of <em>7 sports channels</em> and 4 non-sports channels o<em>ut of 11 channels.</em>
The probability that one <em>TV will be not be showing a sports channel</em>, P(not S), is:
- P(not S) = number of non-sports channels / number of channels.
The <em>best prediction</em> on <em>how many TVs will not be showing a sports channel </em>is, the expected value, which is equal to the number of TVs mulitplied by P(not S):
- P(not S) = 110 × 4/11 = 40.
Since this is a random variable, the expected value is not the exact number of TV but just a probability.
Hence, the answer is the option <em>B: There will be close to 40 TVs but probably not exactly 40 TVs not showing a sports channel.</em>
