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3 years ago

Given: cos∅ =-4/5 , sinФ = -12/13 , ∅ is in the third quadrant, and Ф is in the fourth quadrant. Evaluate Sin(∅+Ф)

Mathematics

1 answer:

galina1969 [7]3 years ago

4 0

Answer:

63/65

Step-by-step explanation:

the angles are in fourth and third quadrants so all the sin and cos values are minus

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The cost, C(x),for manufacturing x units of certain product Is given byC(x)=x^2-20x+35, find the units manufactured at a cost of

Rainbow [258]

Answer:

No units

Step-by-step explanation:

The cost function is given by;

$C(x)=x^2-20x+35$

To find the units manufactured at a cost of $5,560

We equate the C(x) to 5560 and solve for x.

$x^2-20x+35 = 5560$

$x^2-20x+35 - 5560 = 0$

$x^2-20x - 5525= 0$

The discriminant of this equation is negative.

That is,

$d = {( - 20)}^{2} - 4 \times 1 \times - 5560 \: < 0$

Hence the equation has no real roots.

This means no units can be produced at $5,560

7 0

2 years ago

I learn maths and I don't know how to solve this problem.

Lyrx [107]

Answer:

As we get closer to x=-3, the limit is approaches -1, on both sides of -3 so this is a good limit so c is 8.

Step-by-step explanation:

In order for a limit to exists, the left side limit must exist and right side limit must exist and on top of that, they must be equal to each other.

In this case, this a piece wise function and by definition of a limit that exist, the limit of this piece wise function as x approaches 3 from either side, must be equal.

We let x=-3 for the top equation.

$( - 3) {}^{2} - 10 = - 1$

So we set the second equation equal to -1.

$- ( {x}^{2} ) + c = - 1$

$- ( - 3 {}^{2} ) + c = - 1$

$- 9 + c = - 1$

$c = 8$

So the value of c is 8. We can prove this by graphing as well.

5 0

2 years ago

M is directly proportional to r2.when r=2,m=14.Work out the value of m when r=12

valentinak56 [21]

Answer:

504

Step-by-step explanation:

In the attached file

Hope it helps

4 0

2 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$