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ch4aika [34]
2 years ago
9

Susan is buying juice for a party. She wants to buy as many bottles of juice as possible, but she only has $10.00 to spend. If e

ach bottle of juice costs $1.35, how can Susan calculate the number of bottles that she can buy?
A.Divide $10.00 by $1.35, and round the quotient down to the nearest whole number.
B.Divide $10.00 by $1.35, and round the quotient up to the nearest whole number.
C.Divide $1.35 by $10.00, and round the quotient down to the nearest whole number.
D.Subtract $1.35 from $10.00, and round the difference down to the nearest whole number
GIVING BRAINLIEST
Mathematics
1 answer:
UkoKoshka [18]2 years ago
4 0

Answer:I think it is A

Step-by-step explanation:

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you have a part time job. you work 3 hours on friday and 6 hours on saturday. you also receive an allowance of $20 per a week. y
klemol [59]
$92/week is the amount of money you gained from work combined with your $20/week allowance money. 

92 - 20 = 72 (total money made per week subtract allowance money leaves money made from work)
Thus, you make $72/week at your part time job.

You work a total of 9 hours. (3hrs on Fri & 6hrs on Sat added together)
72/9 = 8 (total amount of money made divided by the 9 hrs you worked for - gives amount of money you make per hour)
Thus, you make $8/hr at your part time job.


8 0
3 years ago
In a group of 10 people, there are 4 people that have the flu virus. Suppose we pick 3 random persons to test in order to determ
Murljashka [212]

Answer:

Tests is 100% Accurate, so by using the formula of random variable probability.

Step-by-step explanation:

Total number of people = 10

Sample space = p(A) = 10

Number of people that have flu = n(s) = 4

Pick random 3 persons, the possibility that they have flue is n(A) = ?

Let X is the random variable, consisting of number of positive flu test,

Tests is 100% Accurate, so by using the formula of random variable probability, we get

  P(X) = n (A) / n(S)

  P(X)      = ¾, is the probability of having positive flu test

5 0
3 years ago
At the end of a recent WNBA regular season, the Phoenix murmur had 12 more victories than losses. The number of victories they h
Hoochie [10]

Answer:

34 games


Step-by-step explanation:

let the number of losses be  l

let the number of victories be  v


<u>the Phoenix murmur had 12 more victories than losses:</u>

v=l+12

<u>The number of victories they had was one more than two times the number of losses:</u>

v=2l+1


<em>We have 2 expressions for v, equating these 2, we can solve for l:</em>

l+12=2l+1\\12-1=2l-l\\11=l

So 11 games, they lost.

Using this value, we can plug into the 1st equation to solve for v:

v=l+12\\v=11+12\\v=23

So 23 games, they won.


Given that no draws, they played a total of 23 + 11 = 34 games this season

6 0
3 years ago
Leon made more baskets than Jaden but fewer baskets than Jeremiah. Who made more baskets, Jeremiah or Jaden?
snow_lady [41]

Answer:

I’m pretty sure it’s Jeremiah

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
If x^3 + 1/x^3 = 110 then find x + 1/x
Svetlanka [38]
Use:(a+b)^3=a^3+3a^2b+3ab^2+b^3\ (*)\\\\x^3+\left(\dfrac{1}{x}\right)^3\\=\underbrace{x^3+3\cdot x^2\cdot\dfrac{1}{x}+3\cdot x\cdot\left(\dfrac{1}{x}\right)^2+\left(\dfrac{1}{x}\right)^3}_{(*)}-3\cdot x^2\cdot\dfrac{1}{x}-3\cdot x\cdot\left(\dfrac{1}{x}\right)^2\\\\=\left(x+\dfrac{1}{x}\right)^3-3x-3\cdot\dfrac{1}{x}=\left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)

therefore

x^3+\left(\dfrac{1}{x}\right)^3=110\iff \left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)=110\\\\subtitute\ t=x+\dfrac{1}{x}\\\\t^3-3t=110\ \ \ \ |subtract\ 110\ from\ both\ sides\\\\t^3-3t-110=0\\\\t^3-25t+22t-110=0\\\\t(t^2-25)+22(t-5)=0\ \ \ |use\ a^2-b^2=(a-b)(a+b)\\\\t(t-5)(t+5)+22(t-5)=0\\\\(t-5)[t(t+5)+22]=0\iff t-5=0\ or\ \underbrace{t^2+5t+22=0}_{no\ solution}\\\\t=5\iff x+\dfrac{1}{x}=5\\\\Answer:\boxed{x+\dfrac{1}{x}=5}
3 0
3 years ago
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