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elena-s [515]
3 years ago
5

Explain why 3.6 tenths equal 36 tenths

Mathematics
2 answers:
balu736 [363]3 years ago
6 0
Well there are two ways too look at this

1) divide 36 by 10

2) multiply 3.6 by 10
Assoli18 [71]3 years ago
5 0
I would simply solve the fraction as a division question. To divide 36 by 10, just move the decimal one place to the left. That gives you 3.6
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please help me. In the circle below, U is the center, VX is a diameter, and m VW = 110 degrees Use this information to fill in t
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Answer:

Step-by-step explanation:

Inscribed angle → ∠VXY

(Angle included between two chords meeting at a point on circumference)

Minor arc → (arc VY)

(Arc measuring less than 180° is called as minor arc)

Semicircle → (arc VWX)

(Arc inscribed by the diameter)

m(arc VWX) = 180°

(Semicircle)

m(∠VUW) = 110°

(Central angle subtended by an arc)

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Suppose the point (a, b) lies in the first quadrant. Describe how you would move
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Answer:

To move from (a, b) to (a, -b) move down 2b. The point (a, -b) would be in quadrant 4 and would be a reflection across the x-axis of the point (a, b)

Step-by-step explanation:

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3 years ago
Identify the segments that are parallel, if any, if FDC = GCH
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Answer:

B

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
How can i find the area of square and a rectangle
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8 0
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11/ 42 Marks
amm1812

Answer:

(a)x=128 degrees

(b)\angle APD\neq 116^\circ

Step-by-step explanation:

\angle ABD+\angle CBD =180^\circ$ (Linear Postulate)\\\angle ABD+116^\circ =180^\circ\\\angle ABD=180^\circ-116^\circ\\\angle ABD=64^\circ

(a) Now:

\angle AOD=2 \times \angle ABD$ (Angle at the centre is twice the  angle at the circumference)\\x=2 \times 64^\circ\\x=128^\circ

(b)

\angle APD=2 \times \angle ABD$ (Inscribed Angle Theorem)\\\angle APD=2 \times 64^\circ\\ \angle APD=128^\circ

\angle APD\neq 116^\circ

7 0
3 years ago
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