<span>-8 < x -3 < 1
we have two inequations:
* -8<x-3 and -8+3<x-3+3 or -5 < x or x>-5
* x-3<1 or x-3+3<1+3 and we have x<4
For all cases we have -5<x<4
or </span><span>interval notations: x</span>∈(-5;4)
have fun
It’s corresponding angles
Pythagorean Theorem
3*3+8*8=x*x
9+64=x*x
73=x*x
x=√73≈8.5
Answer:
Area of the circle is 6.25π sq.unit
Step-by-step explanation:
The centre of the circle is at the mid point of a diameter. Th mid point of the diameter is at (5+22,5+12)or(72,3),which is centre. Radius is the distance from end point (5,5)to centre (72,3)∴r=√(5−72)2+(5−3)2=√1.52+4=√6.25=2.5∴
Area of the circle is Ac=π⋅r2=π⋅2.52=6.25π sq.unit[Ans]
Vas happenin!
Hope your day is going well
I think it’s A
Sorry if it’s wrong
Hope this helps *smiles*
