Ask question

Ask question

All categories

3 years ago

13

Please help me [Trig]

1 answer:

yanalaym [24]3 years ago

4 0

Using The base and height dimensions we can find angle A.

Tan(Angle) = Opposite / Adjacent.

Tan(A) = 5/12

A = arctan(5/12)

A = 22.6 degrees.

You might be interested in

Subtract <br><br> \frac{3n+2}{n-4}-\frac{n-6}{n+4}

aalyn [17]

(3n+2)/(n-4) - (n-6)/(n+4)

common denominator (n-4)(n+4)

{(n+4)(3n+2)-(n-4)(n-6)}/{(n-4)(n+4)}

Use the foil method:

{(3n²+14n+8)-(n²-10n+24)}/{(n-4)(n+4)}

distribute negative sign:

{(3n²+14n+8-n²+10n-24)}/{(n-4)(n+4)}

subtract:

(2n²+24n-16)/{(n-4)(n+4)}

take out 2:

2{n²+12n-8}/{(n-4)(n+4)}

4 0

3 years ago

Read 2 more answers

for v= 4i - 5j, find unit vector u in the direction of v, and write your answer as a linear combination of the standard unit vec

umka21 [38]

Answer:

a. $u=\frac{4\sqrt{41}i }{41}-\frac{5\sqrt{41}j}{41}$

Step-by-step explanation:

The given vector is v= 4i - 5j

The magnitude of this vector is;

$|v|=\sqrt{(-4)^2+(-5)^2}$

$|v|=\sqrt{16+25}$

$|v|=\sqrt{41}$

The unit vector u in the direction of v is;

$u=\frac{v}{|v|}$

$u=\frac{4i - 5j}{\sqrt{41}}$

$u=\frac{4i }{\sqrt{41}}-\frac{5j}{\sqrt{41}}$

We rationalize to get

$u=\frac{4\sqrt{41}i }{41}-\frac{5\sqrt{41}j}{41}$

4 0

3 years ago

Read 2 more answers

If I equals PRT which equation is equivalent to T

snow_lady [41]

I = P · R · T
Divide both sides by P·R
I/(P·R) = T

Answer: $\frac{I}{PR} = T$

7 0

3 years ago

Determine weather the following is real or complex <br> i^6-122-7i^2

Leona [35]

Answer:

Real

Step-by-step explanation:

i^6-122-7i^2

(i^2)^3-122-7i^2

(-1)^3-122-7×(-1)

-1-122+7

-123+7

-116

So the final answer is -116

7 0

3 years ago

What is the simplest form of 2(sqr rt) 3/ (sqr rt) 6??

eduard

Answer:

<u>Option A </u>will be your answer

Step-by-step explanation:

hope it's helpful...

5 0

3 years ago