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marishachu [46]

3 years ago

12

Give an example of a situation when it would be appropriate to round a number and a situation in which it would not be appropria

te to round a number. Explain the difference in the situations.

1 answer:

anzhelika [568]3 years ago

8 0

A number might be rounded when determining the number of people who will attend a basketball game. A number should not be rounded when determining the number of students who will participate in a chemistry lab. Only an estimate is needed for attendance at a basketball game because everyone will still get to see the game. In a chemistry lab the correct number of students should be known so that everybody has the proper equipment to use.

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Is freezing outside on a cold day conduction convection or radiation?

harina [27]

<span>Conduction is the process of freezing outside on a cold day. Conduction is usually the process of transfer of heat that is temperature from one body to another body which the difference in their heat energy. This transfer of energy which makes it freeze is also considered as conduction.</span>

7 0

4 years ago

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Please explain how to solve 17 and 18

andriy [413]

Answer:

17. h = l − l cos θ

18. 1.40 m

Explanation:

Let's call d the height of the triangle. We can then say:

h = l − d

Using trig, we can write d in terms of l and θ:

d = l cos θ

h = l − l cos θ

If l = 6 m and l cos θ = 40°:

h = 6 − 6 cos 40

h ≈ 1.40

3 0

3 years ago

In the first stage of a two-stage Carnot engine, energy is absorbed as heat Q1 at temperature T1 = 500 K, work W1 is done, and e

Nataly [62]

Answer:

Efficiency = 52%

Explanation:

Given:

First stage

heat absorbed, Q₁ at temperature T₁ = 500 K

Heat released, Q₂ at temperature T₂ = 430 K

and the work done is W₁

Second stage

Heat released, Q₂ at temperature T₂ = 430 K

Heat released, Q₃ at temperature T₃ = 240 K

and the work done is W₂

Total work done, W = W₁ + W₂

Now,

The efficiency is given as:

$\eta=\frac{\textup{Total\ work\ done}}{\textup{Energy\ provided}}$

or

Work done = change in heat

thus,

W₁ = Q₁ - Q₂

W₂ = Q₂ - Q₃

Thus,

$\eta=\frac{(Q_1-Q_2)\ +\ (Q_2-Q_3)}{Q_1}}$

or

$\eta=1-\frac{(Q_1-Q_3)}{Q_1}}$

or

$\eta=1-\frac{(Q_3)}{Q_1}}$

also,

$\frac{Q_1}{T_1}=\frac{Q_2}{T_2}=\frac{Q_3}{T_3}$

or

$\frac{T_3}{T_1}=\frac{Q_3}{Q_1}$

thus,

$\eta=1-\frac{(T_3)}{T_1}}$

thus,

$\eta=1-\frac{(240\ K)}{500\ K}}$

or

$\eta=0.52$

or

Efficiency = 52%

8 0

4 years ago

Please help!!! I will mark brainliest asap, this is due in 10 minutes!

VARVARA [1.3K]

Answer:

speed

(distance per time)

Kathy is faster btw

4 0

4 years ago

Read 2 more answers

The orbital motion of Earth around the Sun leads to an observable parallax effect on the nearest stars. For each star listed, ca

Murrr4er [49]

Answer:

Following are the answer to this question:

Explanation:

Formula:

$D(PC) =\frac{1}{parallax}\\\\D(av)=D(PC) \times 20.626\ J$

Calculating point A:

when the value is $0.38$

$\to 0.38 \toD(PC)= \frac{1}{0.38}\\\\$

$=2.632$

$\to D(a.v) = \frac{1}{0.38} \times 206265\\$

$=542,802.6$

Calculating point B:

when the value is $0.75$

$\to D(PC)=\frac{1}{0.75}$

$=1.33$

$\to D(a.v) = \frac{1}{0.75} \times 206265\\$

$=275,020$

Calculating point C:

when the value is $0.28$

$\to D(PC)=\frac{1}{0.28}$

$=3.571$

$\to D(a.v) = \frac{1}{0.28} \times 206265\\$

$=736660.7$

Calculating point D:

when the value is $0.42$

$\to D(PC)=\frac{1}{0.42}$

$=2.38$

$\to D(a.v) = \frac{1}{0.42} \times 206265\\$

$=490910.7$

Calculating point E:

when the value is $0.31$

$\to D(PC)=\frac{1}{0.31}$

$=3.226$

$\to D(a.v) = \frac{1}{0.31} \times 206265\\$

$=665370.97$

6 0

3 years ago