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Mice21 [21]
3 years ago
12

How many centimeters are there in 9.3 meters

Physics
2 answers:
galben [10]3 years ago
4 0

Answer:

930 centimeters

Explanation:

Kobotan [32]3 years ago
3 0

Answer:

9.3 m = 930 cm

Explanation:

1 meter = 100 centimeters

so, 9.3 m = 9.3 × 100 = 930 centimeters

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The density of an object is how much matter it contains.<br> True or False?
vlabodo [156]

Answer:

true

Explanation:

8 0
3 years ago
Read 2 more answers
Please help me people
saveliy_v [14]

Answer :

(1) The density of asphalt is, 1200kg/m^3

(2) (a) Length, width and thickness of sheet in meter is, 0.35 m, 1.1 m and 0.015 m respectively.

(b) The volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

Explanation :

<u>Part 1 :</u>

As we are given:

Mass of block = 90 kg

Volume of block = 0.075m^3

Formula used :

\text{Density of block}=\frac{\text{Mass of block}}{\text{Volume of block}}

Now put all the given values in this formula, we get:

\text{Density of block}=\frac{90kg}{0.075m^3}=1200kg/m^3

Thus, the density of asphalt is, 1200kg/m^3

<u>Part 2(a) :</u>

As we are given that:

Length of aluminium sheet = 35 cm

Width of aluminium sheet = 11 dm

Thickness of aluminium sheet = 15 mm

Now we have to convert these dimensions into meters.

Conversions used:

1 cm = 0.01 m

1 dm = 0.1 m

1 mm = 0.001 m

Length of aluminium sheet = 35 cm = 35 × 0.01 = 0.35 m

Width of aluminium sheet = 11 dm = 11 × 0.1 = 1.1 m

Thickness of aluminium sheet = 15 mm = 15 × 0.001 = 0.015 m

<u>Part 2(b) :</u>

First we have to calculate the volume of aluminium sheet.

Volume of aluminum sheet (cuboid) = Length × Width × Thickness

Volume of aluminum sheet (cuboid) = 0.35 m × 1.1 m × 0.015 m

Volume of aluminum sheet (cuboid) = 0.005775 m³

Now we have to calculate the mass of aluminium sheet.

\text{Density of aluminium}=\frac{\text{Mass of aluminium}}{\text{Volume of aluminium}}

2700kg/m^3=\frac{\text{Mass of aluminium}}{0.005775m^3}

\text{Mass of aluminium}=15.59kg

Thus, the volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

7 0
3 years ago
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A charge Q acts on a point charge to create an electric field. Its strength, measured a distance of 40 cm away is 100 N/C. What
KIM [24]

Answer:

E_2=80N/C

Explanation:

From the question we are told that:

Initial Distance d_1=40cm=>0.4m

Initial Electric field strength E_1=100N/C

Final Distance d_2=20cm=>0.20m

Generally the equation for Electric field is mathematically given by.

 E=\frac{kq}{d^2}

 q=\frac{100*(0.4)^2}{K}

Substituting q for d=20cm

 E_2=\frac{k}{0.2}*\frac{100*(0.4)^2}{K}

 E_2=80N/C

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As a space shuttle moves through the dilute ionized gas of Earth's ionosphere, the shuttle's potential is typically changed by -
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Sphere x, of mass 2 kg, is moving to the right at 10m/s. sphere y, of mass 4 kg, is moving to the left at 10m/s. the two spheres
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20m/s, honestly I have know idea what the asnwer is but if i had to guess, this would be my answer.
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