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3 years ago

Please explain how to solve 17 and 18

Physics

1 answer:

andriy [413]3 years ago

3 0

Answer:

17. h = l − l cos θ

18. 1.40 m

Explanation:

Let's call d the height of the triangle. We can then say:

h = l − d

Using trig, we can write d in terms of l and θ:

d = l cos θ

h = l − l cos θ

If l = 6 m and l cos θ = 40°:

h = 6 − 6 cos 40

h ≈ 1.40

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At t=0, a block A of mass 8 kg and block B of mass 16 kg are both at position x=0 . Block A is at rest, and block B is moving at

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The center of mass of the two objects is the average position of the parts of the two object system

The center of mass of block A, and block B after displacement of block B is at 20 m from block A

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The given parameters are;

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Mass of block B, m₂ = 16 kg

Speed of block A = 0 m/s

Speed of block B, v₂ = 10 m/s

Location of the center of mass of the two object at t = 3 s; Required

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The location of block A, after 3 s is x₁ = 0 (block A is at rest)

The location of block B, = v₂ × t

The location of block B, after 3 s is x₂ = 10 m/s × 3 s = 30 m

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$x_{cm} = \dfrac{m_1 \cdot x_1 +m_2\cdot x_2}{m_1 + m_2}$

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3 years ago

What is the energy in joules of a mole of photons associated with visible light of wavelength 486 nm?

ivann1987 [24]

Answer:

$2.46\cdot 10^5 J$

Explanation:

The energy of a single photon is given by:

$E=\frac{hc}{\lambda}$

where

h is the Planck constant

c is the speed of light

$\lambda$ is the wavelength

For the photon in this problem,

$\lambda=486 nm=4.86\cdot 10^{-7}m$

So, its energy is

$E_1=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.86\cdot 10^{-7}m}=4.09\cdot 10^{-19} J$

One mole of photons contains a number of photons equal to Avogadro number:

$N_A = 6.022\cdot 10^{23}$

So, the total energy of one mole of photons is

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7 0

4 years ago

A maple tree seed fell 180 centimeters straight toward the ground at a constant velocity. It moved that distance in 1.5seconds.

denis23 [38]

Answer: 1.2 m/s

Explanation:

Velocity $V$ is defined as the variation of position of an object or body in time. So, if we know the distance the seed traveled and the time, we can calculate its velocity:

$V=\frac{d}{t}$

Where:

$d=180 cm \frac{1 m}{100 cm}=1.8 m$ is the distance the maple seed traveled

$t=1.5 s$ is the time

Then:

$V=\frac{1.8 m}{1.5 s}$

$V=1.2 m/s$ This is the seed's velocity

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