D. Was a leader in the woman's suffrage movement
<span>The core finally cools into a white dwarf, then a black dwarf. This is what happens when a normal-sized star dies. If a really huge star dies, it has so much mass that after the helium is used up, it still has enough carbon to fuse it into heavy elements like iron. When the core turns to iron, it no longer burns.
please give me </span>Brainliest answer?
Answer:
![-16\omega sin(\omega t + \pi/4)](https://tex.z-dn.net/?f=-16%5Comega%20sin%28%5Comega%20t%20%2B%20%5Cpi%2F4%29)
Explanation:
The function of the current with respect to time is the derivative of the charge function with respect to time t. We can apply chain rule to differentiate it:
![I(t) = Q'(t) = (16cos(\omega t + \pi/4))' \\= -16(\omega t + \pi/4)' sin(\omega t + \pi/4) \\= -16\omega sin(\omega t + \pi/4)](https://tex.z-dn.net/?f=I%28t%29%20%3D%20Q%27%28t%29%20%3D%20%2816cos%28%5Comega%20t%20%2B%20%5Cpi%2F4%29%29%27%20%5C%5C%3D%20-16%28%5Comega%20t%20%2B%20%5Cpi%2F4%29%27%20sin%28%5Comega%20t%20%2B%20%5Cpi%2F4%29%20%5C%5C%3D%20-16%5Comega%20sin%28%5Comega%20t%20%2B%20%5Cpi%2F4%29)
Answer:
temperature change is 262.06°K
Explanation:
given data
mass = 0.07 kg
velocity = 258 m/s
to find out
what is its temperature change
solution
we know here
heat change Q is is equal to kinetic energy that is
KE = 0.5 × m× v² ...........1
here m is mass and v is velocity
KE = 0.5 × 0.07 × 258²
KE = 2329.74 J
and we know
Q = mC∆t .................2
here m is mass and ∆t is change in temperature and C is 127J/kg-K
so put here all value
2329.74 = 0.07 × 127 × ∆t
∆t = 262.06
so temperature change is 262.06°K