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4 years ago

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Please help!!:):):):)

1 answer:

Nitella [24]4 years ago

4 0

Answer:

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Which are the solutions of x2 = –11x + 4?

Zarrin [17]

For this case we have the following polynomial:

$x ^ 2 = -11x + 4$

Rewriting the polynomial we have:

$x ^ 2 + 11x - 4 = 0$

From here, we can solve the polynomial using the quadratic equation

We have then:

$x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$

$x=\frac{-11+/-\sqrt{11^2-4(1)(-4)}}{2(1)}$

$x=\frac{-11+/-\sqrt{11^2+16}}{2}$

$x=\frac{-11+/-\sqrt{121+16}}{2}$

$x=\frac{-11+/-\sqrt{137}}{2}$

Therefore, the solutions are:

$x=\frac{-11+\sqrt{137}}{2}$

$x=\frac{-11-\sqrt{137}}{2}$

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