Question

Which are the solutions of x2 = –11x + 4?

Answer 1

For this case we have the following polynomial:

$x ^ 2 = -11x + 4$

Rewriting the polynomial we have:

$x ^ 2 + 11x - 4 = 0$

From here, we can solve the polynomial using the quadratic equation

We have then:

$x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$

$x=\frac{-11+/-\sqrt{11^2-4(1)(-4)}}{2(1)}$

$x=\frac{-11+/-\sqrt{11^2+16}}{2}$

$x=\frac{-11+/-\sqrt{121+16}}{2}$

$x=\frac{-11+/-\sqrt{137}}{2}$

Therefore, the solutions are:

$x=\frac{-11+\sqrt{137}}{2}$

$x=\frac{-11-\sqrt{137}}{2}$

Answer 2

The correct answer is option A.

I just did the quiz to this and got it right.

Hope this helps and have a gr8 day <3