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melisa1 [442]
3 years ago
13

What’s the scientific notation for 3,207,000,000

Mathematics
1 answer:
Pani-rosa [81]3 years ago
8 0

Answer:

3.207 x 10^{9}

Step-by-step explanation:

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Translate this sentence into an equation. 48 is the product of Greg’s score and 3. Use the variable g to represent Greg’s score
ratelena [41]

Answer:

G x 3 = 48

Step-by-step explanation:

let G be Greg's score

And product means multiplication.

so G x 3 = 48.

finding Greg's score means 3g = 48.

g = 48/3

g = 16.

6 0
3 years ago
Help pls
antoniya [11.8K]

Answer:

The first blank is BAL and FGH

The second blank is AL

The third blank is CE and KI

The fourth and final blank is GH

explanation

i got a 5/5 on the symmetry edmentum test

8 0
2 years ago
I need these questions answered ASAP thx!!
Korvikt [17]

A) profit is 8$, the price increases 8$ every time or each pie is $4

B)N times 4= P

C) 15 times 4= $60 Profit. Because each pie is 4$

D) if 144$ are made and each pie is $4, you’d divide 144 by 4= 36. 36 Pies were sold.

I hope this is correct and helps :)

6 0
3 years ago
Find the y-intercept of the parabola y = x2 + 6x.<br><br> Can somebody help?
WINSTONCH [101]

Given:

The equation of the parabola is:

y=x^2+6x

To find:

The y-intercept of the parabola.

Solution:

We have,

y=x^2+6x

Putting x=0 in the given equation, we get

y=(0)^2+6(0)

y=0+0

y=0

Therefore, the y-intercept of the parabola is 0. It means the y-intercept of the given parabola is at point (0,0).

6 0
2 years ago
Use the surface integral in​ Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus
Tom [10]

Stokes' theorem says the integral of the curl of \vec F over a surface S with boundary C is equal to the integral of \vec F along the boundary. In other words, the flux of the curl of the vector field is equal to the circulation of the field, such that

\displaystyle\iint_S\nabla\times\vec F\cdot\mathrm d\vec S=\int_C\vec F\cdot\mathrm d\vec r

We have

\vec F(x,y,z)=x^2\,\vec\imath+4x\,\vec\jmath+z^2\,\vec k

\implies\nabla\times\vec F(x,y,z)=4\,\vec k

Parameterize the ellipse S by

\vec s(u,v)=\dfrac{u\cos v}{\sqrt5}\,\vec\imath+\dfrac{u\sqrt5\sin v}4\,\vec\jmath

with 0\le u\le1 and 0\le v\le2\pi.

Take the normal vector to S to be

\dfrac{\partial\vec s}{\partial\vec u}\times\dfrac{\partial\vec s}{\partial\vec v}=\dfrac u4\,\vec k

Then the flux of the curl is

\displaystyle\iint_S4\,\vec k\cdot\dfrac u4\,\vec k\,\mathrm dA=\int_0^{2\pi}\int_0^1u\,\mathrm du\,\mathrm dv=\boxed{\pi}

4 0
3 years ago
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