Answer:
The three digit number = 951
Step-by-step explanation:
Let suppose the numbers are:
= abc
According to given condition:
a+ b + c = 15 -------------eq1
Also, given the difference between the first two digit = the difference between the last two digits:
==> l a-b l = l b-cl
==> (a-b) = (b-c)
==> (a+c) = 2b
Now we will substitue in eq1
==> a+ b + c = 15
==> 2b + b = 15
==> 3b = 15
Dividing both sides by 3 we get:
b =5
a + c = 2b
a+ c = 10
a = 10 -c ..........(2)
We know that"
(a-b) = (b-c)
==> a > b+c
==> a > 5 + c
==> 10 -c > 5 +c
==>5 > 2c
==> 2.5 > c
As c is an odd number so c will be equal to 1
c = 1
a = 10 -1
a = 9
The three digit number = 951
The hundred digit is greater than the sum of the tens and ones digits
i hope it will help you!
Answer:
g = (h+a) - l
None of them
Step-by-step explanation:
Suppose your car has h liters of engine oil in the morning. During the day, some oil may have leaked, you may have added more oil, or both. The oil level in the evening is g liters. Which of the following expressions always represents how far away the new oil level is from the previous oil level? H+G lGl none of them
Let
h = liters of oil in the morning
l= liters that has leaked
a= liters that were added during the day
g= amount of liters at the end of the evening
Total liters of oil in the evening= (litres of oil in the morning + litres of oil added during the day) - litres of oil that leaked
Substituting each variable into the formula, we have
g = (h+a) - l
Answer:
H0 : μ = 6.2
H1 : μ ≠ 6.2
Step-by-step explanation:
Population mean, μ = 6.2 ppm
The hypothesis :
Null, H0 : = The mean level of Ozone is normally 6.2 ppm ;
The alternative hypothesis is the researcher's claim that the current ozone level is not normal, that is it may be higher or lower than the normal value in ppm
Hence, the hypothesis could be written as :
H0 : μ = 6.2
H1 : μ ≠ 6.2
If i am understanding the question correctly, x<10
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