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Zigmanuir [339]
3 years ago
6

For a standard normal distribution find the approximate value of p(z<0.42)

Mathematics
2 answers:
Kruka [31]3 years ago
8 0

Answer:

p(z<0.42) = 0.6628

Step-by-step explanation:

A normal distribution with a mean of 0 and a standard deviation of 1 is called a standard normal distribution. That is to say:

μ = 0

σ² = 1

Using a calculator, we find that:

p(z<0.42) = 0.6628 (See picture attached)

Eva8 [605]3 years ago
5 0

Answer:

0.66276.

Step-by-step explanation:

We are asked to find the approximate value of p(z<0.42) for a standard normal distribution.

Our given expression means the probability of getting a z-score less than 0.42.

We need to find the probability of getting the area corresponding to a z-score less than 0.42 under normal distribution curve.

We will normal distribution table to solve our given problem.

p(z

Therefore, the approximate value of our given expression would be 0.66276.

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3 years ago
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siniylev [52]

Answer:

Hence Domain set for function is {0,1,2,3,4}

Step-by-step explanation:

Given:

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Now domain mean all possible value for input so that it gives real output as per condition mentioned

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3 years ago
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