Ask question

Ask question

All categories

4 years ago

15

Which equation represents the word sentence? The product of 4 and a number increased by 6 is 30. A. 4x – 6 = 30 B. 4x = 30 + 6 C

. 4x + 6 = 30 D. 4x + 30 = 6

1 answer:

Mila [183]4 years ago

4 0

The product of 4 and a number increased by 6 is 30 would be written like this;

4x + 6 = 30

You might be interested in

Please help me, and I will mark you as brainliest

Lostsunrise [7]

Answer:

what is the equation that u actually looking for?

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Is 6^-2 positive or negative? Explain.

Gnoma [55]

Answer:

It's positive when you have 6^-2 it's the same as having $(\frac{1}{6})^{2} \\$ . So 6^-2 it's 1/36.

Step-by-step explanation:

7 0

4 years ago

Which rays are part of line BE?<br><br> AC and AE<br> AB and AE<br> AC and AB<br> AB and

rosijanka [135]

We are given a diagram with different rays and lines.

Note: A line can be extend more and more upto infinitely length from both of the ends but a ray can be extend from from end only.

We need to find the rays for the line BE.

We can see BE line has a point A in between line.

So, we can name the rays formed with end point A as AB and AE.

<h3>Therefore, AB and AE rays are part of line BE.</h3><h3>So, the correct option is 2nd option :</h3><h3>AB and AE.</h3>

4 0

3 years ago

Read 2 more answers

240,000 written as a whole number multiplied by the power of ten

Stolb23 [73]

This question can be also asked as what is the scientific notation of the number 240,000. The scientific notation is written as <span>a whole number multiplied by the power of ten. It should be written as follows:

2.4 x 10^5

Hope this helps. Have a nice day.</span>

8 0

4 years ago

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

3 years ago