Answer with Step-by-step explanation:
We are given that
For each real number 
To prove that f is one -to-one.
Proof:Let 
and 
be any nonzero real numbers such that
By using the definition of f to rewrite the left hand side of this equation
Then, by using the definition of f to rewrite the right hand side of this equation of
Equating the expression then we get
Therefore, f is one-to-one.
Answer:
what
Step-by-step explanation:
Answer: Any pictures or more information?
Step-by-step explanation: Really happy to help you
The general equation for a circle,
, falls out of the Pythagorean Theorem, which states that the square of the hypotenuse of a right triangle is always equal to the sum of the squares of its legs (you might have seen this fact written like
, where <em>a </em>and <em>b</em> are the legs of a right triangle and <em>c </em>is its hypotenuse. When we fix <em /><em>c</em> in place and let <em>a </em>and <em>b </em>vary (in a sense, at least; their values are still dependent on <em>c</em>), the shape swept out by all of those possible triangles is a circle - a shape defined by having all of its points equidistant from some center.
How do we modify this equation to shift the circle and change its radius, then? Well, if we want to change the radius, we simply have to change the hypotenuse of the triangle that's sweeping out the circle in the first place. The default for a circle is 1, but we're looking for a radius of 6, so our equation, in line with Pythagorus's, would look like
, or
.
Shifting the center of the circle is a bit of a longer story, but - at first counterintuitively - you can move a circle's center to the point (a,b) by altering the x and y portions of the equation to read:
Answer:
y = 8•6^x
Step-by-step explanation:
Here, we want to write an exponential equation
To fully write this, we need the values of a and b
From the first coordinates given;
8 = a•b^0
a = 8 since b^0 = 1
Furthermore;
288 = 8•b*2
b^2 = 36
b = √36
b = 6
So we have ;
y = 8•6^x
