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White raven [17]
2 years ago
14

What is the multiple of 7 that are between 44 and 54

Mathematics
1 answer:
Sergio039 [100]2 years ago
4 0

Answer:

49 is your only answer........

Step-by-step explanation:

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The zeros of a function are the values of x for which the function is equal to zero. Enter a number in each blank to make trued
scoray [572]

Answer:

zeros are 4 and 3

Step-by-step explanation:

2x - 6 =0

x -4 = 0

solve both of these for x

these are your zeros

7 0
3 years ago
5=1/3(2x+12)<br><br> Solve for X in simplest form
garik1379 [7]

9514 1404 393

Answer:

  x = 3/2

Step-by-step explanation:

Multiply by 3 and solve the resulting 2-step equation.

  5 = (1/3)(2x +12)

  15 = 2x +12 . . . . . . multiply by 3

  3 = 2x . . . . . . . . . . subtract 12

  3/2 = x . . . . . . . . . . divide by 2

4 0
3 years ago
Calculate cose to two decimal places.
Monica [59]

Answer:

B. 0.69

Step-by-step explanation:

Law of Cosines: cos A = (b² + c² - a²) / 2bc

cosθ = (7² + 11² - 8²) / 2*7*11 = 106/154 = 0.688 ≈ 0.69

4 0
3 years ago
a regular rectangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface ar
Margarita [4]
A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)

Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say x.

The lateral faces are equilateral triangles of side length x.

The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18  cm^2.

now we need to find x. Consider the picture attached, showing one lateral face of the pyramid.

by the Pythagorean theorem: 

h= \sqrt{ x^{2} - (x/2)^{2}}= \sqrt{ x^{2}- x^{2}/4}= \sqrt{3x^2/4}= \frac{ \sqrt{3} }{2}x

thus, 

Area_{triangle}= \frac{1}{2}\cdot base \cdot height\\\\18= \frac{1}{2}\cdot x \cdot \frac{ \sqrt{3} }{2}x\\\\ \frac{18 \cdot 4}{ \sqrt{3}}=x^2

thus:

x^2 =\frac{18 \cdot 4}{ \sqrt{3}}= \frac{18 \cdot 4 \cdot\  \sqrt{3} }{3}=24 \sqrt{3}       (cm^2)

but x^{2} is exactly the base area, since the base is a square of sidelength = x cm.


So, the total surface area = base area + lateral area =  24 \sqrt{3}+72   cm^2


Answer: 24 \sqrt{3}+72   cm^2

4 0
3 years ago
Can you use the SAS postulate, the AAS theorem, or bothto prove the triangles are congruent
NikAS [45]
Yes, most definitely
I hope that this helps!

3 0
3 years ago
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