When a water gun is fired while being held horizontally at a height of 1.00 m above ground level, the water travels a horizontal
distance of 5.00 m. a child, who is holding the same gun in a horizontal position, is also sliding down a 45.0° incline at a constant speed of 2.00 m/s.if the child fires the gun when it is 1.00 m above the ground and the water takes 0.329 s to reach the ground, how far will the water travel horizontally?
1 answer:
Refer to the diagrams shown below.
Neglect air resistance.
Case A.
Let t = the time of flight.
Then for horizontal travel,
t = (5 m)/(u m/s) = 5/u s
For vertical travel,
1.0 m = (1/2)*(9.8 m/s²)*(5/u s)²
5/u = √(1/4.9) = 0.4518
u = 11.0668 m/s
Case B.
There are two contributions to the horizontal velocity
(i) 11.0668 m/s
(ii) (2 m/s)*cos(45) = 1.4142 m/s
The total horizontal velocity is
11.0668 + 1.4142 = 12.481 m/s
Because the time of flight is 0.329 s, the horizontal distance traveled is
d = (12.481 m/s)*(0.329 s) = 4.106 m
Answer: The horizontal distance traveled is 4.11 m
Neglect air resistance.
Case A.
Let t = the time of flight.
Then for horizontal travel,
t = (5 m)/(u m/s) = 5/u s
For vertical travel,
1.0 m = (1/2)*(9.8 m/s²)*(5/u s)²
5/u = √(1/4.9) = 0.4518
u = 11.0668 m/s
Case B.
There are two contributions to the horizontal velocity
(i) 11.0668 m/s
(ii) (2 m/s)*cos(45) = 1.4142 m/s
The total horizontal velocity is
11.0668 + 1.4142 = 12.481 m/s
Because the time of flight is 0.329 s, the horizontal distance traveled is
d = (12.481 m/s)*(0.329 s) = 4.106 m
Answer: The horizontal distance traveled is 4.11 m
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"Beam AB has a negligible mass and thickness, and supports the 200kg uniform block. It is pinned at A and rests on the top of a post, having a mass of 20 kg and negligible thickness. Determine the two coefficients of static friction at B and at C so that when the magnitude of the applied force is increased to 360 N , the post slips at both B and C simultaneously."
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Answer:
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