Answer:
The intensity of light from the 1mm from the central maximu is
Explanation:
From the question we are told that
The wavelength is
The width of the slit is
The distance from the screen is
The intensity at the central maximum is
The distance from the central maximum is
Let z be the the distance of a point with intensity I from central maximum
Then we can represent this intensity as
Now the relationship between D and z can be represented using the SOHCAHTOA rule i.e
if the angle between the the light at z and the central maximum is small
Then
Which implies that
substituting this into the equation for the intensity
given that
We have that