Determine the area under the standard normal curve that lies to the left of (a) z equals negative 1.53 commaz=−1.53, (b) z equ
als negative 1.51z=−1.51, (c) z equals negative 0.87z=−0.87, and (d) z equals negative 0.63z=−0.63. (a) The area to the left of zequals=negative 1.53−1.53 is nothing. (Round to four decimal places as needed.)
1 answer:
Answer:
(a) z = -1.53 --> P(x<z) = 0.0630
(b) z = -1.151 --> P(x<z) = 0,0655
(c) z = -0.63 --> P(x<z) = 0,2643
Step-by-step explanation:
To know the area that lies to the left, equal to P(x<z), the best way is to look at tables of standard normal curve.
(a) z = -1.53 --> P(x<z) = 0.0630
(b) z = -1.151 --> P(x<z) = 0,0655
(c) z = -0.63 --> P(x<z) = 0,2643
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Answer:
x = 63.6
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X and also the area to its left. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to its right.
In this problem, we have that:
Find a value of x that has area 0.01 to its right
This is x when Z has a pvalue of 1-0.01 = 0.99. So it is X when Z = 2.3267.
So x = 63.6