Determine the area under the standard normal curve that lies to the left of (a) z equals negative 1.53 commaz=−1.53, (b) z equ
als negative 1.51z=−1.51, (c) z equals negative 0.87z=−0.87, and (d) z equals negative 0.63z=−0.63. (a) The area to the left of zequals=negative 1.53−1.53 is nothing. (Round to four decimal places as needed.)
1 answer:
Answer:
(a) z = -1.53 --> P(x<z) = 0.0630
(b) z = -1.151 --> P(x<z) = 0,0655
(c) z = -0.63 --> P(x<z) = 0,2643
Step-by-step explanation:
To know the area that lies to the left, equal to P(x<z), the best way is to look at tables of standard normal curve.
(a) z = -1.53 --> P(x<z) = 0.0630
(b) z = -1.151 --> P(x<z) = 0,0655
(c) z = -0.63 --> P(x<z) = 0,2643
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