Question

Determine the area under the standard normal curve that lies to the left of ​(a) z equals negative 1.53 commaz=−1.53, ​(b) z equals negative 1.51z=−1.51​, ​(c) z equals negative 0.87z=−0.87​, and​ (d) z equals negative 0.63z=−0.63. ​(a) The area to the left of zequals=negative 1.53−1.53 is nothing. ​(Round to four decimal places as​ needed.)

Answer 1

Answer:

(a) z = -1.53 --> P(x<z) = 0.0630

(b) z = -1.151 --> P(x<z) = 0,0655

(c) z = -0.63 --> P(x<z) = 0,2643

Step-by-step explanation:

To know the area that lies to the left, equal to P(x<z), the best way is to look at tables of standard normal curve.

(a) z = -1.53 --> P(x<z) = 0.0630

(b) z = -1.151 --> P(x<z) = 0,0655

(c) z = -0.63 --> P(x<z) = 0,2643