<span>f(-10)=12, x = -10, y = 12
f(16)=-1, x = 16, y = -1.
so, we have two points, let's check with that,
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![\bf \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)} y-12=-\cfrac{1}{2}[x-(-10)] \\\\\\ y-12=-\cfrac{1}{2}(x+10)\implies y-12=-\cfrac{1}{2}x-5\implies y=-\cfrac{1}{2}x+7](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%20y-12%3D-%5Ccfrac%7B1%7D%7B2%7D%5Bx-%28-10%29%5D%0A%5C%5C%5C%5C%5C%5C%0Ay-12%3D-%5Ccfrac%7B1%7D%7B2%7D%28x%2B10%29%5Cimplies%20y-12%3D-%5Ccfrac%7B1%7D%7B2%7Dx-5%5Cimplies%20y%3D-%5Ccfrac%7B1%7D%7B2%7Dx%2B7)
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Answer:
X ~ N(27, 4) ;
xbar ~ N(27, 0.1026) ;
0.5 ;
0.5
Step-by-step explanation:
Probability distribution of X : N(μ, σ²)
μ = 27 ; σ = 2
X ~ N(μ, σ²) = X ~ N(27, 2²) ;X ~ N(27, 4)
Distribution is approximately normal ; μ = xbar ; xbar = 27
(Standard Error)² = (σ/√n)²= (2/√39)² = 0.1026
xbar ~ N(μ, σ²) = xbar ~ N(27, 2²) ; xbar ~ N(27, 0.1026)
Probability that a randomly selected individual found a job in less than 27 weeks :
P(X < 27) :
Obtain the Zscore :
Z = (x - μ) / σ
Z = (27 - 27) / 2 = 0/2
Z = 0
P(Z < 0) = 0.5
D.) n = 36
P(X < 27) :
Obtain the Zscore :
Z = (x - μ) / σ/√n
Z = (27 - 27) / (2/√36) = 0/0.33333
Z = 0
P(Z < 0) = 0.5
Answer:
104
Step-by-step explanation:
8x3=24 then you carry over the 2 and 8x1=8 and 8+2=10 so the awnser is 104
The answer is b=3 for your problem
Answer:
128
Step-by-step explanation:
(4^2)(4)(2)
128
