Answer:
Question
Answers
Related Questions
Subtract the following:
A) 18 rupees 9 paise from 75 rupees 80 paise.
B) 49 rupees 79 paise from 123 rupees 68 paise.
Answer
VerifiedVerified
139.5k+ views
17.4k+ likes
Hint: Use decimal concept.
We know that, 1 rupee = 100 paise. We can reframe these questions as follows:
18 rupees 9 paise from 75 rupees 80 paise
18 rupees 9 paise can be represented as 18.09 rupees and 75 rupees 80 paise can be represented as 75.80 rupees. Now, on subtracting we’ll get,
75.80−18.09−−−−−− 57.71
Which means 57 rupees 71 paise
49 rupees 79 paise from 123 rupees 68 paise
49 rupees 79 paise can be represented as 49.79 rupees and 123 rupees 68 paise can be represented as 123.68 rupees. Now, on subtracting we’ll get,
123.68 −49.79−−−−−− 73.89
Which means 73 rupees 89 paise.
Note: We can also perform the subtraction by making all units the same that are paise and then subtract.
Answer:
$10.80
Step-by-step explanation:
Given:
Total number of CDs = 6
Cost price (including tax) = $71.40
Each CD had a tax of $1.10
To find the price of each CD before tax Let's first find the price of each CD after tax.
Price after tax =
Price of each CD after tax = $11.90
Since each CD had a tax of $1.10, price of each CD before tax would be : $11.90 - $1.10 = $10.80
Therefore price of each CD before tax is $10.80
Answer:
23(14) +23(33)
Step-by-step explanation:
23(14+33)
Distributive Property
Answer:
Option B is correct.
Step-by-step explanation:
6 3/7 = 45/7
1 3/6 = 9/6 = 3/2
=> 45/7 - 3/2
=> 90/14 - 21/14
=> 69/14
=> 4 13/14
Therefore, Option B is correct.
Answer:
<h2>see below</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>given:</h3>
- f(x)=3x³-2x²-12x+8
- -a×-b=ab
- -a×b=-ab
- a²-b²=(a+b)(a-b)
<h3>to do:</h3>
- use factor theorem to show that (x+2) is a factor of f(x)
<h3>tips and formulas:</h3>
- When f(c)=0 then x−c is a factor of f(x)
<h3>let's solve:</h3>
according to the question
x+2=0
x=-2
therefore
we have proven that x+2 is a factor of 3x³-2x²-12x+8
let's factorise 3x³-2x²-12x+8
- factor out x²: x²(3x-2)-12x+8
- factor out -4: x²(3x-2)-4(3x-2)
- group: (x²-4)(3x-2)
- use a²-b² = (a+b)(a-b):
and
we are done