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AysviL [449]
3 years ago
6

Help me with my homework I’m trying to do two things at once

Chemistry
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

Your more likekly to see a metor

Explanation:

because astirod are to fast to hit earth

You might be interested in
Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of water is pro
sergeinik [125]

The question is incomplete, here is the complete question:

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water. If 12.5 g of water is produced from the reaction of 72.6 g of sulfuric acid and 77.0 g of sodium hydroxide, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.

<u>Answer:</u> The percent yield of water in the reaction is 46.85 %.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For NaOH:</u>

Given mass of NaOH = 77.0 g

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

\text{Moles of NaOH}=\frac{77.0g}{40g/mol}=1.925mol

  • <u>For sulfuric acid:</u>

Given mass of sulfuric acid = 72.6 g

Molar mass of sulfuric acid = 98 g/mol

Putting values in equation 1, we get:

\text{Moles of sulfuric acid}=\frac{72.6g}{98g/mol}=0.741mol

The chemical equation for the reaction of NaOH and sulfuric acid follows:

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of NaOH

So, 0.741 moles of sulfuric acid will react with = \frac{2}{1}\times 0.741=1.482mol of NaOH

As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent.

Thus, sulfuric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of sulfuric acid produces 2 moles of water

So, 0.741 moles of sulfuric acid will produce = \frac{2}{1}\times 0.741=1.482moles of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.482 moles

Putting values in equation 1, we get:

1.482mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.482mol\times 18g/mol)=26.68g

To calculate the percentage yield of water, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of water = 12.5 g

Theoretical yield of water = 26.68 g

Putting values in above equation, we get:

\%\text{ yield of water}=\frac{12.5g}{26.68g}\times 100\\\\\% \text{yield of water}=46.85\%

Hence, the percent yield of water in the reaction is 46.85 %.

8 0
3 years ago
Causes of flooding ??
kkurt [141]

Answer:

Heavy rains

overflowing

Broken Dams

3 0
3 years ago
What are the functions of respiratory system​
VMariaS [17]

Answer:

Your lungs are part of the respiratory system.

Explanation:

A group of organs and tissues that work together to help you breathe.The respiratory system's main job is to move fresh air into your body while removing waste gases.

Was this helpful?

If so let me know and please mark me brainiest.

6 0
2 years ago
The correct electron configuration for magnesium is: 1s 22s 22p 63s 3 True False
Dmitry [639]

Answer:

False

Explanation:

Magnesium is the element of second group and third period. The electronic configuration of magnesium is - 2, 8, 2 or 1s^22s^22p^63s^2

There are 2 valence electrons of magnesium.

Only the valence electrons are shown by dots in the Lewis structure.  

As, stated above, there are only two valence electrons of magnesium, so in the Lewis structure, two dots are made around the magnesium symbol.

Given that the electronic configuration is:- 1s^22s^22p^63s^3 .

Orbital s cannot accommodate 3 electrons and also in magnesium it has 3s^2 . Hence, the statement is false.

7 0
3 years ago
Choose the correct answer for each by circling a letter
Nikitich [7]
D 
-Hope it helped! :D
3 0
3 years ago
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