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lakkis [162]
1 year ago
15

question if the following elements were involved in a chemical reaction, which one would be most likely to form a cation? respon

ses potassium (k) chlorine (cl) fluorine (f) nitrogen (n)
Chemistry
1 answer:
Serjik [45]1 year ago
5 0

Fluorine (F) would be least likely to form a cation out of potassium, fluorine, chlorine, and nitrogen.

  • A cation is a positively charged atom (or molecule) that has lost electrons (or electrons).
  • The tendency for electropositive elements to lose electrons and produce cations is greater. On the left side of the periodic table, these are often metals.
  • Going down a group increases electropositivity, or the propensity to lose electrons and generate cations. and decreases across a period. In the given examples:
  • Potassium, K is an alkali metal and will lose electrons readily to form a cation.
  • Nitrogen (N), Fluorine (F), and chlorine (Cl) are all nonmetals that prefer to accept electrons and form anions instead. F is the most electronegative i.e. it will gain electrons and form F- rather than F+.

To learn more about cation visit:

brainly.com/question/28710898

#SPJ4

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Volume is the quantity of two-dimensional space occupied by a liquid, solid, or gas.
expeople1 [14]

Answer:

B.False

Explanation:

Volume is used in 3D shapes, 2D is found by area.

Hope this helps please mark as brainliest ^^

3 0
4 years ago
Read 2 more answers
A coffee-cup calorimeter contains 140.0 g of water at 25.1°C . A 124.0-g block of copper metal is heated to 100.4°C by putting i
Kisachek [45]

Answer:

(a) 3347 J; (b) 3043 J; (c) 58 J/K; (d) 35.5 °C  

Explanation:

(a) Heat lost by copper

The formula for the heat lost or gained by a substance is

q =mCΔT

ΔT = T₂ - T₁= 30.3 °C - 100.4 °C = -70.1 °C = -70.1 K

q = 124.0 g × 0.385 J·K⁻¹g⁻¹ × (-70.1 K) = -3347 J

The negative sign shows that heat is lost.

The copper block has lost 3347 J.

(b) Heat gained by water

ΔT = 30.3 °C - 25.1 °C = 5.2 °C = 5.2 K

q = 140.0 g × 4.18 J·K⁻¹g⁻¹ × 5.2 K = 3043 J

The water has gained 3043 J.

(c) Heat capacity of calorimeter

Heat lost by Cu = heat gained by water + heat gained by calorimeter

The temperature change for the calorimeter is the same as that for the water.

ΔT = 5.2 K

\begin{array}{rcl}\text{3347 J} & = & \text{3043 J} + C \times \text{5.2 K}\\\text{304 J} & = & 5.2C \text{ K}\\C & = & \dfrac{\text{304 J}}{\text{5.2 K}}\\\\& = & \text{58 J/K}\\\end{array}

The heat capacity of the calorimeter is 58 J/K.

(d) Final temperature of water

\begin{array}{rcl}\text{Heat lost by copper } + \text{Heat gained by water}& = &0 \\\text{Heat lost by copper}& = &-\text{Heat gained by water} \\m_{\text{Cu}}C_{\text{Cu}}\Delta T_{\text{Cu}}& = & -m_{\text{w}}C_{\text{w}}\Delta T_{\text{w}}\\\end{array}\\

\begin{array}{rcl}\text{124.0 g} \times \text{0.385 J$\cdot$K$^{-1}$g$^{-1}$}\times \Delta T_{\text{Cu}}& = & -\text{140.0 g} \times 4.18 \text{ J$\cdot$ K$^{-1}$g$^{-1}$}\times \Delta T_{\text{w}}\\\text{47.7 J$\cdot$K$^{-1}$}\times \Delta T_{\text{Cu}}& = &-\text{585 J$\cdot$ K$^{-1}$g}\times \Delta T_{\text{w}}\\\Delta T_{\text{Cu}} & = & -12.26\Delta T_{\text{w}}\\\end{array}

\begin{array}{rcl}\Delta T_{\text{f}} - 100.4 \, ^{\circ}\text{C} & = & -12.26(\Delta T_{\text{f}} - 30.3\, ^{\circ}\text{C})\\\Delta T_{\text{f}} - 100.4 \, ^{\circ}\text{C} & = & -12.26\Delta T_{\text{f}} + 371\, ^{\circ}\text{C}\\13.26\Delta T_{\text{f}} & = & 471\, ^{\circ}\text{C}\\\Delta T_{\text{f}} & = & 35.5\, ^{\circ}\text{C}\\\end{array}

The final temperature of the water would be 35.5 °C.

7 0
3 years ago
(d) Solid lithium nitride conducts electricity and is used in batteries. Why would you expect solid lithium nitride not to condu
guapka [62]

Answer:

Solid ionic compounds do not conduct electricity because the ions are held firmly in place. The ions cannot move to conduct the electric current. But when an ionic compound melts, the charged ions are free to move. Therefore, molten ionic compounds do conduct electricity.

3 0
3 years ago
Why is it that the higher the molecular mass of the alkane, the higher the boiling point? Refer to intermolecuar forces and ener
AnnZ [28]

Answer:

Higher melting and boiling points signify stronger noncovalent intermolecular forces. Consider the boiling points of increasingly larger hydrocarbons. More carbons means a greater surface area possible for hydrophobic interaction, and thus higher boiling points.

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3 years ago
indicate if the following statements are true or false for a standard galvanic cell. oxidation occurs at the anode reduction occ
Masja [62]

An anode is an electrode, it can be a metal or another conductor. in an electrochemical cell that is polarized if an electric current flows into it. Electric current flows opposite to the direction of movement of electrons. In electrochemical processes, both galvanic cells (batteries) and electrolysis cells, anodes undergo oxidation.

In contrast to an Anode, a Cathode is an electrode pole in an electrochemical cell that is polarized if this pole is positively charged (so that an electric current will flow out of it, or the movement of electrons will enter this pole).

In galvanic cells or power plants (batteries), the anode is the negative pole. The electrode will release electrons towards the circuit and hence an electric current flows into this electrode and makes it an anode and negative.

6 0
1 year ago
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