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3 years ago

Calculate the number of moles of solute present in 185.0 mL of a 1.50 mol/L solution of HCl.

Chemistry

1 answer:

____ [38]3 years ago

4 0

Answer:

0.278 mol HCl

Explanation:

We currently have 185.0 mL of a 1.50 mol/L solution of HCl. We want to find the number of moles there are.

Based on the given information, our volume is 185.0 mL and our molarity is 1.50. Because molarity is defined as moles / Litre, we can easily find the moles given volume by multiplying molarity by volume.

First, though, we must convert millilitres to litres. There are 1000 mL in 1 L, so divide 185.0 by 1000:

185.0 / 1000 = 0.185 L

Now, multiply 0.185 by 1.50:

0.185 L * 1.50 mol/L = 0.278 mol HCl

Thus the answer is 0.278 mol HCl.

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Answer:

0.9433g

Explanation:

Theoretical yield is defined as the mass produced assuming all reactant reacts producing the product.

Assuming the reaction is 1:1, we need to find the moles of E-stilbene (Reactant). If all reactant reacts, the moles of E-stilbene = Moles of product.

Using the molar mass of the product we can find the theoretical yield as follows:

Moles E-stilbene:

0.50g * (1mol/180.25g) = 0.00277 moles = Moles Product

Mass Product = Theoretical yield:

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3 years ago

Two elements are studied. One has atomic number X and one has atomic number X+2. It is known that element X is a halogen. To wha

vladimir2022 [97]

Answer:

Group 1 (or IA)

Explanation:

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For each extra unit of atomic number, the group number increases by 1. That means that the X+1 element would belong to the group 18 (or VIIIA). The X+2 element would thus belong in the group 1 (or IA) one period higher (higher as in numeric value, not as in position in the periodic table).

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3 years ago

Which of the following is true about two neutral atoms of the element gold?

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C is correct on this problem

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3 years ago

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200.0 mL of 3.85 M HCl is added to 100.0 mL of 4.6 M barium hydroxide. The reaction goes to completion. What is the concentratio

Ede4ka [16]

Answer:

2.387 mol/L

Explanation:

The reaction that takes place is:

2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

First we calculate how many moles of each reagent were added:

HCl ⇒ 200.0 mL * 3.85 M = 203.85 mmol HCl

Ba(OH)₂ ⇒ 100.0 mL * 4.6 M = 460 mmol Ba(OH)₂

460 mmol of Ba(OH)₂ would react completely with (2*460) 920 mmol of HCl. There are not as many mmoles of HCl so Ba(OH)₂ will remain in excess.

Now we calculate how many moles of Ba(OH)₂ reacted, by converting the total number of HCl moles to Ba(OH)₂ moles:

203.85 mmol HCl * $\frac{1mmolBa(OH)_{2}}{2mmolHCl}$ = 101.925 mmol Ba(OH)₂

This means the remaining Ba(OH)₂ is:

460 mmol - 101.925 mmol = 358.075 mmoles Ba(OH)₂

There are two OH⁻ moles per Ba(OH)₂ mol:

OH⁻ moles = 2 * 358.075 = 716.15 mmol OH⁻

Finally we divide the number of OH⁻ moles by the total volume (100 mL + 200 mL):

716.15 mmol OH⁻ / 300.0 mL = 2.387 M

So the answer is 2.387 mol/L

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3 years ago

Element Q has an atomic number 68. Consider the isotope Q-136 how many protons are in a neutral atom of this isotope?

mote1985 [20]

Answer: 68

Explanation:

Isotopes of an element have same number of protons but different number of neutrons. Which means isotopes of an element have same atomic number but different mass number.

Atomic number is equal to the number of protons or the number of electrons for a neutral atom and is specific to a particular element.

Mass number is the sum of number of protons and the number of neutrons.

Given : atomic number of element Q = 68 = number of protons

Mass number of isotope Q-136 = 136

But as isotopes have same atomic number, the number of protons will be same and hence there are 68 protons are in a neutral atom of this isotope.

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3 years ago