Question

Calculate the number of moles of solute present in 185.0 mL of a 1.50 mol/L solution of HCl.

Answer 1

Answer:

0.278 mol HCl

Explanation:

We currently have 185.0 mL of a 1.50 mol/L solution of HCl. We want to find the number of moles there are.

Based on the given information, our volume is 185.0 mL and our molarity is 1.50. Because molarity is defined as moles / Litre, we can easily find the moles given volume by multiplying molarity by volume.

First, though, we must convert millilitres to litres. There are 1000 mL in 1 L, so divide 185.0 by 1000:

185.0 / 1000 = 0.185 L

Now, multiply 0.185  by 1.50:

0.185 L * 1.50 mol/L = 0.278 mol HCl

Thus the answer is 0.278 mol HCl.

~ an aesthetics lover