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Kitty [74]
2 years ago
10

for each question on a five question multiple choice test, there are four possible answers which exactly one is correct. A stude

nt, who did not study or attend class, is going to select his answeres is completely at random. If the random variable x represents the number of correct answers he selects, write the probability distribution of the random varuable x
Mathematics
1 answer:
Natasha2012 [34]2 years ago
4 0

Answer:

X follows a Binomial Distribution with n = no. of questions and p = ¼

X ~ B(n , 0.25)

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Naddik [55]

Answer:

Step-by-step explanation:

7) ∠1  + 30 = 180                {linear pair}

            ∠1 = 180 - 30

            ∠1 = 150

8)  ∠2 = 30    {Vertically opposite angles are congruent}

9) In ΔLMN,

∠L + ∠N + ∠M = 180   {angle sum property of triangle}

50 + 30 + ∠M = 180

       80 + ∠M = 180

                ∠M = 180 - 80

                ∠M = 100°

10) Sum of exterior angle of a triangle equals to sum of opposite interior angles.

∠B + ∠A = ∠BCD

30 +   ∠A = 80

        ∠A  = 80 - 30

      ∠A = 50

4 0
2 years ago
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How much gas will John have in the tank when he arrives in Fresno
olya-2409 [2.1K]

Can you please insert a diagram next time or a picture since We don't know any other information. It's completely impossible to answer this without more information.  

7 0
2 years ago
8. Find the measure of the third angle of a triangle given that the first two angles are 44o and 72 o. Show your work.
iren [92.7K]

44+72=116

180-116=64

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3 years ago
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Find the x-intercept for y = 3x^2 + 6x − 10
azamat

Answer:

x-intercepts: (-3.08, 0) and (1.08, 0)

Step-by-step explanation:

Given:

The function is given as:

y=3x^2+6x-10

In order to find the x-intercept, we need to equate the given function to 0 as x-intercept is the point where the 'y' value is 0. So,

y=0\\3x^2+6x-10=0

Now, this is a quadratic equation of the form ax^2+bx+c=0

We find the solution using the quadratic formula,

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Here, a=3,b=6,c=-10

Now, the solutions are:

x=\frac{-6\pm \sqrt{6^2-4(3)(-10)}}{2(3)}\\\\x=\frac{-6\pm \sqrt{36+120}}{6}\\\\x=\frac{-6\pm \sqrt{156}}{6}\\\\x=\frac{-6}{6}-\frac{2\sqrt{39}}{6}\ or\ x=\frac{-6}{6}+\frac{2\sqrt{39}}{6}\\\\x=-1-2.08\ or\ x=-1+2.08\\\\x=-3.08\ or\ x=1.08

Therefore, the x-intercepts are (-3.08, 0) and (1.08, 0)

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3 years ago
Only lunarokami12 do this
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Answer:

Step-by-step explanation:

yes

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