Write and solve an equation to

Mathematics

2 answers:

Leno4ka [110]2 years ago

8 0

Answer:

a. 13; Equation = 2N - 7 = 19

b. 2; 8 - 3N = 2

Step-by-step explanation:

a. 2N - 7 = 19

- 2N - 7 + 7 = 19 + 7

- 2N = 26 = 13

2 2

b. 8 - 3N = 2

8 - 8 - 3N = 2 - 8

- 3N = -6 = 2

-3 -3

Harman [31]2 years ago

3 0

Answer:

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Step-by-step explanation:

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PLEASE HELP AS QUICKLY AS POSSIBLE THANK YOU :)

Temka [501]

Answer:

106

Step-by-step explanation:

The area of one of the triangles is 1/2*5*3

The area is 7.5, but there are 2 triangles so the combined area is 15

The area for whole rectangle is 7*(5+3+5)=7*13=91

So the total area is 91+15= 106

7 0

3 years ago

Read 2 more answers

How to solve this? \int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x

ivanzaharov [21]

$\Large \mathbb{SOLUTION:}$

$\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes} \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}$