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OLga [1]
2 years ago
10

Write and solve an equation to

Mathematics
2 answers:
Leno4ka [110]2 years ago
8 0

Answer:

a. 13; Equation = 2N - 7 = 19

b. 2; 8 - 3N = 2

Step-by-step explanation:

a. 2N - 7 = 19

  - 2N - 7 + 7 = 19 + 7

  <u>- 2N</u> = <u>26</u> = 13

     2       2

b. 8 - 3N = 2

 8 - 8 - 3N = 2 - 8

 <u>- 3N</u> = <u>-6</u> = 2

    -3      -3

Harman [31]2 years ago
3 0

Answer:

who knows what is going on with you

Step-by-step explanation:

sorry for my mis behavior I am very sorry for it I am going to delete app now

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Volume and surface area are often compared by manufacturers in order to maximize how much of something can go inside of a packag
notka56 [123]
We have no dimensions to work with. I'll pick some and try and comply with the conditions of the problem. 

Suppose you have an object that is 14 by 22 by 27 cm. These three numbers have no common factor so they cannot be reduced any further, which is helpful for this problem.

Find the Volume
Volume

l = 27 cm
w = 14 cm
h = 22 cm

V = 27 *14 * 22
V = 8316 cm^3

Find the surface area
SA = 2*l*w + 2*l*h  + 2*w*h
SA = 2*27*14  +  2*27*22   +  2*14*22
SA = 756 + 1188 + 616
SA = 2558

Just looking at these numbers The surface area is about 1/3 of the volume. I don't think this is always true.


 \frac{SA}{V} =  \frac{2*L*W  + 2*L*H + 2*W*H}{L*W*H} 

Another way to do this is to consider a cube which might give you a more useful result. 

s = L = W = H all three dimensions are equal in a cube.
The volume of a cube is s*s*s = s^3
The surface area of a cube is 2*s*s + 2*s*s + 2s*s = 6s^2

\frac{SA_cube}{V_cube} =  \frac{6s*s}{s*s*s}
\frac{SA}{V} =  \frac{6}{s}

That means whatever the side length, the Surface Area to volume = 6/the side length which is kind of an interesting result.


4 0
3 years ago
1 +5x2 + (1 + 3) to the second power
GarryVolchara [31]

Answer:

27

Step-by-step explanation:

1 + (5)(2) + (1 + 3)^2

1 + 10 + (1 + 3)^2

11 + (1+3)^2

11+4^2

11+16

27

<h3><u>Hope this helps! Have an amazing day!</u></h3>
4 0
2 years ago
Possible answers:<br> A) 336cm <br> B) 110m<br> C) 588m<br> D) 1,029m
kozerog [31]

Answer: The area of the enclosure is 1,029 square meters

Step-by-step explanation: The first thing is to use the unit of measurement required by the question, and to do this we need to convert what we have to what is required.

If the scale of the diagram is given as every 4cm represents 7m, that means, every unit of the actual measurement would be given as

(X/4) x 7

For the length of the enclosure, we can determine that as follows;

Length = (28/4) x 7

Length = 7 x 7

Length = 49m

And for the width,

Width = (12/4) x 7

Width = 3 x 7

Width = 21m

Therefore, the area is calculated as,

Area = L x W

Area = 49 x 21

Area = 1029 m²

5 0
2 years ago
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A regulation basketball hoop has a rim with an 18-inch diameter. What is the approximate length around the rim of a regulation b
MrRissso [65]
You are looking for the circumference. which is C(circumference)= \pi x r (radius)
the radius is =to half of the diameter.
c=56.55
3 0
2 years ago
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Find the length of AB .<br> E<br> 12<br> B<br> D<br> AB
aivan3 [116]

Answer:

23

Step-by-step explanation:

8 0
3 years ago
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