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max2010maxim [7]

3 years ago

14

Joey asked all of his friends how many times they visited the zoo this year. The dot plot shown here displays the responses that

Joey recorded?
A) 8

B) 9

C) 10

D) 11

1 answer:

bagirrra123 [75]3 years ago

5 0

Wheres the dot plot at?

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Number 18 plz. I really need help

elixir [45]

The answer is 87. it was quite simple

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3 years ago

Morgan lives 4/5 of a mile from the park. Stanley lives 1/3 of that distance. How far does Stanley live from the park?

olya-2409 [2.1K]

I hope this helps you

4/5-1/3

(4.3/5.3)-(1.5/3.5)

12/15-5/15

7/15

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2 years ago

What is the fractional equivalent of 225%?

vitfil [10]

You would start out by putting 225 over 100 then simplifying from there. You would end up getting 9/4. As a mixed number that would be 2 and 1/4.

7 0

3 years ago

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3x - 51y + 24 and 3(x- 17y + 8)

dlinn [17]

Answer:

They are equal if that’s what you’re asking

Step-by-step explanation:

3 0

2 years ago

Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A

alekssr [168]

Answer:

$\theta_{CAB}=128.316$

$\theta_{ABC}=25.842$

$\theta_{BCA}=25.842$

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

$r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

$AB= \sqrt{(-3-1)^2+(0-3)^2}=5$

$BC= \sqrt{(1-1)^2+(3-(-3))^2}=9$

$CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5$

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

$BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}$

$\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}$

$\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}$

$\theta_{CAB}=\arccos{-\dfrac{0.62}}$

$\theta_{CAB}=128.316$

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

$\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}$

$\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)$

$\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)$

$\theta_{ABC}=\arcsin{0.4359}\right)$

$\theta_{ABC}=25.842$

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

$\theta_{BCA}=25.842$

this can also be checked using the fact the sum of all angles inside a triangle is 180

$\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180$

$25.842+128.316+25.842$

$180$

6 0

3 years ago

Read 2 more answers