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Allushta [10]
3 years ago
13

At a restaurant, four people ordered fried crab cakes and four people ordered a cup of gumbo, with a total of $31. If only two p

eople had ordered the crab cakes and one person ordered the gumbo, the bill would have been $12.25. How much are each order of fried crab cakes and each cup of gumbo? (Can you please show the steps?) Thank you.
Mathematics
1 answer:
ruslelena [56]3 years ago
7 0

Answer:

Fried crab cakes = $4.50

Cup of gumbo = $3.25

Step-by-step explanation:

Let's make the price of fried crab cakes = x and the price of a cup of gumbo = y. Set up two equations for x and y and solve for each variable.

<h3><u>Setting up the equations:</u></h3>

4 people ordered x and 4 people ordered y for a total of 31 dollars, so this equation would look like: 4x + 4y = 31

2 people ordered x and 1 person ordered y for a total of $12.25, so this equation would look like: 2x + y = 12.25

<h3><u>Substitution method:</u></h3>

Now you have your two equations-- solve for a variable in one of the equations and substitute that value into the other equation.

The easiest way to start would be to solve for y in the second equation by subtracting 2x from both sides.

y = 12.25 - 2x

Substitute this value into the first equation.

4x + 4(12.25 - 2x) = 31

Now solve for x-- start by distributing 4 inside the parentheses.

4x + (49 - 8x) = 31

Combine like terms.

-4x + 49 = 31

Subtract 49 from both sides.

-4x = -18

Divide both sides by -4.

x = 4.5

Substitute this value of x into our starting equation for which we solved for y.

2(4.5) + y = 12.25

Multiply 2 and 4.5 together.

9 + y = 12.25

Subtract 9 from both sides.

y = 3.25

Each order of fried crab cakes is worth the x-value [$4.50] and each cup of gumbo is worth the y-value [$3.25].

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Given the information, we have a direct proportionality. Then, the proportions would be:

\frac{7}{x}=\frac{4}{11}

solving for x we get the following:

\begin{gathered} \frac{7}{x}=\frac{4}{11} \\ \Rightarrow7=\frac{4}{11}\cdot x \\ \Rightarrow\frac{7}{\frac{4}{11}}=x \\ \Rightarrow x=\frac{11\cdot7}{4}=\frac{77}{4}=19\frac{1}{4} \\ x=19\frac{1}{4} \end{gathered}

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Each student gets 25/100 of a piece of the poster board.

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Beef hope me I need you to answer the question. What is n * 54 - 688-20 =???³
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Answer:n= 1/3d - 2/3m

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1jaiz4 and 1 more users found this answer helpful

THANKS

1

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Answer

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maxtext75

Helping Hand

15 answers

26 people helped

Answer:

n = d - 2m

        3*

Step-by-step explanation:

First we want to get n alone on one side, so we should subtract 2m from both side;

d = 2m + 3n

3n = d - 2m

Now to get n by itself, we need to divide by 3 from both sides;

3n = d - 2m

n = d - 2m

        3*

*Pretend there is a fraction bar between d - 2m and 3

Step-by-step explanation:

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Answer:

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3 years ago
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Please could you explain this step by step I’m really stuck.
allochka39001 [22]

Answer:

x = -2.5
x = 2

Step-by-step explanation:

Hello!

We can remove the denominators by multiplying everything by it.

Solve:

  • \frac{5}{x + 3} + \frac4{x + 2} = 2
  • 5 + \frac{4(x + 3)}{x + 2} = 2(x + 3)
  • 5 + \frac{4x + 12}{x + 2} = 2x + 6
  • 5(x + 2) +4x + 12 = (2x + 6)(x + 2)
  • 5x + 10 + 4x + 12 = 2x^2 + 6x + 4x + 12
  • 9x + 22 = 2x^2 + 10x + 12

Let's make one side equal to 0.

  • 0 = 2x^2 + x - 10

Solve by factoring, and then the zero product property.

  • 0 = 2x^2 + x - 10\\

Multiply 2 and -10. You get -20. Think of two number that multiply to -20, and add to 1. If we think about the standard form of a quadratic, ax^2 + bx + c, think two numbers that equal "ac" and add up to "b".

  • 0 = 2x^2 - 4x + 5x - 10
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  • 0 = (2x + 5)(x - 2)

Using the zero product property, set each factor to 0 and solve for x.

  1. 2x + 5 = 0
    2x = -5
    x = -5/2 = -2.5
  2. x - 2 = 0
    x = 2

The two answers are x = -2.5, and x = 2.

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