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3 years ago

13

Jayden starts with $1575 in a college savings account. His account earns interest at a rate of 2.7% compounded annually. How muc

h money is in the account after 9 years?

1 answer:

Korolek [52]3 years ago

8 0

Step-by-step explanation:

2.7/100*1575=42.525

then for 9years

9*42.525=$382.725

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Which graph represents the piecewise-defined function?

kifflom [539]

Answer: The first option is correct.

Explanation:

The given piecewise function is,

$y=\begin{cases}-\frac{4}{5}x-3 & \text{ if } x$

From the piecewise function we can say that if x<0, then

$f(x)=-\frac{4}{5}x-3$

If $x\geq2$ , then

$f(x)=3x-10$

Since the f(x) is defined for x<0 and $x\geq2$ , therefore the function f(x) is not defined for $0\leq x$ .

In the graph 2, 3 and 4 for each value of x there exist a unique value of y, therefore the function is defined for all values of x, which is not true according to the given piecewise function.

Only in figure the value of y not exist when x lies between 0 to 2, including 0. It means the function is not defined for $0\leq x$ , hence the first option is correct.

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3 years ago

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Which of the following is the correct classification of ∆mnp if m<m=35° and m<p=47°?

AnnZ [28]

Answer:

D. Obtuse.

Step-by-step explanation:

We are told that in $\Delta MNP$ $m\angle M=35^o$ and $m\angle P=47^o$ . We are asked to classify our given $\Delta MNP$ .

We can see that angle M and angle P are acute angles as their measure is less than 90 degrees.

Let us find the measure of angle P using angle sum property of triangles, which states that sum of interior angles of a triangle is 180 degrees.

So we can set an equation as:

$m\angle M+m\angle P+m\angle N=180^o$

Upon substituting our given values we will get,

$35^o+47^o+m\angle N=180^o$

$82^o+m\angle N=180^o$

$82^o-82^o+m\angle N=180^o-82^o$

$m\angle N=98^o$

As measure of angle N is 98 degrees, so angle N is an obtuse angle.

Since a triangle having an angle that measures more than 90 degrees is called an obtuse triangle, therefore, $\Delta MNP$ is an obtuse triangle and option D is the correct choice.

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3 years ago

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Hilda was simplifying some numerical expressions and made each of the following sequences of calculations. Name the mathematical

Galina-37 [17]

Answer:

Problem 1:

5 · (−4/3) · (2/5)

= (−4/3) · 5 · (2/5) <em>Conmutative Property of Multiplication</em>

= (−4/3) · (5 · (2/5)) <em>Associative Property of Multiplication</em>

= (−4/3) · (2/1) = −8/3 = −2*2/3<em> Multiplied fractions and extracted common factor</em>

Problem 2:

17 + 29 + 3+ 1

= 17 + 3 + 29 + 1 <em>Conmutative Property of Addition</em>

= (17 + 3) + (29 + 1) <em>Associative Property of Addition</em>

= 20 + 30 Added groups

= 50 Added terms

Step-by-step explanation:

<u>For the Problem 1:</u>

In the first step, Hilda applied the <em>Conmutative Property of Multiplication</em>, because she changed the order of the numbers in the product

In the second step, she applied the <em>Associative Property of Multiplication, </em>because she agrouped the product of 5 and<em> </em>2/5 to perform it sepparately

In the third step, she calculated<em> the product of the fractions</em> -4/3 and 2/1, then she extracted 2 as a <em>common factor</em> to express the fraction as -2*2/3

<u>For the Problem 2:</u>

In the first step, Hilda applied the <em>Conmutative Property of Addition, </em>because she changed the order of the numbers in the sum

In the second step, she applied the<em> Associative Property of Addition, </em>because she associated the addition of 17 and 3 and the addition of 29 and 1, to calculate them in groups.

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3 years ago

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Find the missing measure if a and b are the legs of the right triangle and c is the hypotenuse, with a = 11 and c =18.

never [62]

Answer:

$\sqrt{203}$

Step-by-step explanation:

1. $11^{2} + b^{2} = 18^{2}$

2. $b^{2} =203$

3. b = $\sqrt{203}$

Can't be simplified.

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Lana71 [14]

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