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viva [34]
3 years ago
13

Jayden starts with $1575 in a college savings account. His account earns interest at a rate of 2.7% compounded annually. How muc

h money is in the account after 9 years?
Mathematics
1 answer:
Korolek [52]3 years ago
8 0

Step-by-step explanation:

2.7/100*1575=42.525

then for 9years

9*42.525=$382.725

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Change 7 out of 50 into a percentage and change 18 out of 20 into a percentage
Ksivusya [100]
7/50 = 0.14
0.14 x 100 = 14
14%

18/20 = 0.9
0.9 x 100 = 90
90%
3 0
2 years ago
On a board measuring 1x100, each square is numbered from
max2010maxim [7]

Answer:

97

Step-by-step explanation:

Given the following conditions :

board measuring 1x100, each square is numbered from 1 to 100

Three colors are used to paint the squares from left to right in the sequence :

one blue, two reds and three green squares in a repeated pattern.

What is the highest numbered square that is painted blue?

The sequence of painting is repeated after :

(1 + 2 + 3) = 6 successive squares

Since the number of squares = 100

Maximum complete repetition possible :

100 / 6 = 16 remainder 4

Hence 16 * 6 = 96 (the highest complete sequence terminates on the square numbered 96)

On the 97th square, another sequence begins which is a blue and the 100th square is painted the first of the 3 green colors.

Hence, the highest numbered square that is painted blue is 97

5 0
3 years ago
Read 2 more answers
Simplify 1/3 12x - 6<br> A. -2x-1<br> B.-2x-8<br> C.-x+4<br> D.3x+10<br> E. 4x-2
Natali5045456 [20]
1/3(12x - 6)

4x - 2: e
4 0
3 years ago
2850
maxonik [38]
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4 0
2 years ago
What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9
weeeeeb [17]

The difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

<h3>How to determine the difference?</h3>

The expression is given as:

\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}

Factor the denominators of the expressions:

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}

Apply the difference of two squares to x² - 9

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}

Take LCM

\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Hence, the difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Read more about expressions at:

brainly.com/question/723406

#SPJ4

6 0
2 years ago
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