Answer:
Okay...
Step-by-step explanation:
What do you want us to answer?
1. The area of the rectangle is 336. 14 times 24= 336 or width times length= 336.
2. The perimeter of the rectangle is 76. Because, 2 times(14+24)=76
3. If x= 10, the area would still be 336
It equals 10 are supposed to divide the whole line by 3 to get the smaller segment then double it to get the larger segment
Step-by-step explanation:
Initially, let the side of the cubical box is 
inches,
So, the volume of the box, 
.
Given that ![g(x)=\sqrt[3]{x} =\sqrt[3]{a^3}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%20%3D%5Csqrt%5B3%5D%7Ba%5E3%7D)
On doubling the volume of the box, the new volume is 
.
So, ![g(x)=\sqrt[3]{2x} =\sqrt[3]{2a^3}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B2x%7D%20%3D%5Csqrt%5B3%5D%7B2a%5E3%7D)
![\Rightarrow g(x)=\sqrt[3]{2} a \; \cdots (i)](https://tex.z-dn.net/?f=%5CRightarrow%20g%28x%29%3D%5Csqrt%5B3%5D%7B2%7D%20a%20%5C%3B%20%5Ccdots%20%28i%29)
As ![\sqrt[3]{2} >1](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D%20%3E1)
, so the graph of ![g(x)=\sqrt[3]{2} a](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B2%7D%20a)
will be above of the 
as shown in the graph.
The answer is 50.
Hope this helped!
