Inflection point is the point where the second derivative of a graph is zero.
y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2
Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2
Therefore, E(1, pi/2).
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Answer:
Step-by-step explanation:
Answer:
X > -3, 0.28, 4
Step-by-step explanation:
x - 7 > -12 - To solve add 7 to both sides
x > -5 Which means every number GREATER but not EQUAL to 5 will count as a solution to the equation, therefore 5 is not a correct answer. -3 is greater then -5, and any positive number is greater then any negative number.
Therefore the Correct Answer is : -3. 0.28, 4
Answer:
12r^2 +r -7
Step-by-step explanation:
9r^2 +4r -7 +3r^2 -3r
Combine like terms
9r^2 +3r^2 +4r -3r -7
12r^2 +r -7